• 2022-06-17
    以下程序运行结果为#include[stdio.h] void main() { char a[] = "Language", b[] = "programe"; char *p, *q; int k; p = a; q = b; for (k=0; k<8; k++) if (*(p+k) == *(q+k)) printf("%c", *(p+k)); }
    A: gae
    B: ga
    C: Language
    D: programe