计算积分[tex=7.286x2.786]K3118ouU7vsF15ggWM2kbf3KUjkPRKQ1Pnoo90R0EqzrC0A3ShqW0ibKYjjvr9CptYYvz8zI/qOrdlT1RlYo5pV5XKIZPLj7HwWEhNettHG+DcsbY2e34olG58k5nrKF[/tex]

2022-06-17

计算积分[tex=7.286x2.786]K3118ouU7vsF15ggWM2kbf3KUjkPRKQ1Pnoo90R0EqzrC0A3ShqW0ibKYjjvr9CptYYvz8zI/qOrdlT1RlYo5pV5XKIZPLj7HwWEhNettHG+DcsbY2e34olG58k5nrKF[/tex]

答案：

解 显然[tex=2.357x1.0]iYbK/m2HPL4SyxgIH2UTBA==[/tex]是[tex=1.786x1.357]GYJ7X7XJijqizBuSGMrl3g==[/tex]的孤立奇点,而其他使[tex=3.429x1.143]LWe+rR7sm5JU5ZA3tu2I2hrn3Kvo5nMOnDEGxdKDi8o=[/tex]的点 [tex=11.214x1.357]KbKAjecc+cet9ctw8vXEEHJTg3n5kkvRy2zqHpgwOQ85rJ1HI5Hwnxc1jECN8IAMjobK11QuIfT03A2T342/LQ==[/tex] 不在圆周[tex=2.357x1.357]0eFnCGZRH3evsTxph9Jj7w==[/tex]内,故[tex=17.071x2.857]pbDjesDsmpnyPWJqDpTg+QyNAFHEaYKBfCfBX4yCaITAd8TUp82FckmdfvkF53Pc4F0gg86d0ZySfsky4cpKFjbKB4pF4WmqW3ijd40psCG77mKRB7dQIov+QFjUc6a8NlyyB8US7CTqcgAIJVMg/ZG2ndK6Oipo0agijr5ajKDRd3dxqbOjkooq44iQD+sELQ4IOZV6iytD6DbZgFqXIcDMujBW2tpd+mUnrn0sxnKgKk6/gNU/728f/CFj4txs[/tex]由于[tex=2.357x1.0]iYbK/m2HPL4SyxgIH2UTBA==[/tex]的类型不易确定,可以采用计算[tex=1.643x1.214]5Uyz+VIGdYFbpAFb0SSDgQ==[/tex]的方法求留数. 即在[tex=4.714x1.357]4bvaz1d7/Fpsq3fjwrBhVQ==[/tex]内,展开[tex=1.786x1.357]GYJ7X7XJijqizBuSGMrl3g==[/tex]为洛朗级数 :[tex=15.357x14.643]qeiYnKXLEhyhuGRg8yLtr04dhfJnd+K/ZtBmmr0Xzz/E6R5GIXcddWrbAqNE0NT/KSfsdaE51T2xgeCDFs6m7corf0Bgx2pgvfu2hgux6qeoVikfSNjUX8vbw75RAwBpSggGdSCf7aF33LOJS9wj+LfxjWd1BejE0BOc/rpmQ8VYwfbcYTDG61kb+2I1x9YP2pQ7mVNSMFp9T/O/2m24Cciy1CSxCfpNM10CqcGYKWBZpbLVuu1iF3zOq0vFl402W5W1Nrhh3Lb4/3GSQrollNxVGNynvfH9ICwXOOoqK7YnM7emJgpWEQJWwQF1+WXrPTrcucNpvPSkFTu5Z68OeGG0iVa8YGJ6eoBwTblSfhKBCJutomwGNSW806ky03nzwPijsVvVS0ERd1WjYDJVX2hr93FW+m1KrfMRLE4WjHZaeZXYMoEmhmkEXuQEL1z0+ABbJ1hdAFZxIFeIkM7CTi+jbVrUfcq+Nx6hwR9zGda9mUY/KtKat0pLzo5tu7IEns/Q/QG7/V2tBOCS5apq6Ubi/ZmQgEbfPMOmQFZ9/ez9ThkdDOf2e6JvGjMz3xcJeLZg4czTebJhDHAXxFCLofhAllt5oyrdoNgxguk6pxK5uIkbZPPjwNGskAEgfUe52g82IVF329d/f31Xm0NGVA==[/tex]其中 [tex=1.929x1.357]t9jzX2thd7oAj8Yx347QOQ==[/tex] 在点[tex=2.357x1.0]iYbK/m2HPL4SyxgIH2UTBA==[/tex] 解析, 且[tex=3.714x1.286]mMC2PhTVgiu6sr/Ppq3nlssp0IunXRBeh+NfBZSqXXU=[/tex],所以[tex=2.357x1.0]iYbK/m2HPL4SyxgIH2UTBA==[/tex]为[tex=3.643x1.357]vVPCzqodgXFogXArE3FN2uXN9dflyhfwCM/pf50YHVM=[/tex]的一阶极点,有[tex=21.571x2.786]79Wd/JsaQKi3RBB3vwr83/8IiDQuC8bpFaOV7S7xM567eJcdW8FUcaPgs4redEyEwp4COAiPVRpOdsTYNpwd7SsD+t9MW9N/pFLgq3OTotXfrdY+0tuYMrNQGtS8a+aCY3csC4Z66K3eps6MaXW+bAEs1gggHUZxqwSzh/LX42oVgMrAggnKJJ9IJ6//hGSggFk5LKF3mtgrLJYzuDCi4Q==[/tex]从而有[tex=14.643x2.786]pbDjesDsmpnyPWJqDpTg+QyNAFHEaYKBfCfBX4yCaITAd8TUp82FckmdfvkF53Pc4F0gg86d0ZySfsky4cpKFjbKB4pF4WmqW3ijd40psCG77mKRB7dQIov+QFjUc6a8u2AseDzUlNx6szX4/wSsVpP53PCM0QDfD3yGMGapAY5CpP0LlBoitrH2K/+8F9Bx[/tex]

举一反三

内容

0
已知S盒如下表，若输入为100010，则二进制输出为（） [br][/br] 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 7 13 14 3 0 6 9 10 1 2 8 5 11 12 4 15 1 13 8 11 5 6 15 0 3 4 7 2 12 1 10 14 9 2 10 6 9 0 12 11 7 13 15 1 3 14 5 2 8 4 3 3 15 0 6 10 1 13 8 9 4 5 11 12 7 2 14 A: 0110 B: 1001 C: 0100 D: 0101
1
设DES加密算法中的一个S盒为： 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 1 2 3 14 4 13 1 2 15 11 8 3 10 6 12 5 9 0 7 0 15 7 4 14 2 13 1 10 6 12 11 9 5 3 8 4 1 14 8 13 6 2 11 15 12 9 7 3 10 5 0 15 12 8 2 4 9 1 7 5 11 3 14 10 0 6 13 若给定输入为101101，则该S盒的输出的二进制表示为
2
【计算题】5 ×8= 6×4= 7×7= 9×5= 2×3= 9 ×2= 8×9= 7×8= 5×5= 4×3= 5+8= 6 ×6= 3×7= 4×8= 9×3= 1 ×2= 9×9= 6×8= 8×0= 4×7=
3
以下程序段实现的输出是（）。for(i=0;i<;=9;i++)s[i]=i;for(i=9;i>;=0;i--)printf("%2d",s[i]);[/i][/i] A: 9 7 5 3 1 B: 1 3 5 7 9 C: 9 8 7 6 5 4 3 2 1 0 D: 0 1 2 3 4 5 6 7 8 9
4
计算积分[tex=7.286x2.786]K3118ouU7vsF15ggWM2kbf3KUjkPRKQ1Pnoo90R0EqzrC0A3ShqW0ibKYjjvr9CptYYvz8zI/qOrdlT1RlYo5pV5XKIZPLj7HwWEhNettHG+DcsbY2e34olG58k5nrKF[/tex]