298K,p(O2)=100kPa条件下,O2+4H++4e- = 2H2O的电极电势为
A: j /V=jy/V +(0.0591pH)/V
B: j/V =jy/ V –(0.0591V pH)/V
C: j/V =jy/V +(0.0148V pH)/V
D: j/V =jy/V –(0.0148V pH)/V
A: j /V=jy/V +(0.0591pH)/V
B: j/V =jy/ V –(0.0591V pH)/V
C: j/V =jy/V +(0.0148V pH)/V
D: j/V =jy/V –(0.0148V pH)/V
举一反三
- 298K,p(O2)=100kPa条件下,O2+4H++4e-=2H2O的电极电势为( ) 未知类型:{'options': ['φ=[img=15x20]17e0a793aa2a24b.jpg[/img]+0.0591 V pH', ' φ=[img=15x20]17e0a793aa2a24b.jpg[/img]–0.0591 V pH', ' φ=[img=15x20]17e0a793aa2a24b.jpg[/img]+0.0148 V pH', ' φ=[img=15x20]17e0a793aa2a24b.jpg[/img]–0.0148 V pH'], 'type': 102}
- 298K,p(O2)=100kPa条件下,O2+4H++4e-=2H2O的电极电势为() A: φ/V=φ/V+(0.0591pH)/V B: φ/V=φ/V–(0.0591VpH)/V C: φ/V=φ/V+(0.0148VpH)/V D: φ/V=φ/V–(0.0148VpH)/V
- 4 、反应 2N 2 O 5 4NO 2 + O 2 , v (N 2 O 5 ) 、 v (NO 2 ) 、 v (O 2 ) 之间关系正确的是 .. (A) v (N 2 O 5 ) / 2 = v (NO 2 ) / 4 = v (O 2 ) ; (B) v (N 2 O 5 ) = v (NO 2 ) = v (O 2 ) ; (C) 2 v (N 2 O 5 ) = 4 v (NO 2 ) = v (O 2 ) ; (D) 2 v (N 2 O 5 ) = 4 v (NO 2 ) + v (O 2 ) 。/js/editor20131024/themes/default/images/spacer.gif
- 低电压指电压持续低于()。 A: B: ≤2μV C: D: ≤5μV E: F: 5~15μV G: H: 10~25μV I: J: ≤50μV
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