• 2022-06-07
    求“能被3除尽,用5除余2,用8除余5,用11除余8,用14除余11”的正整数,该问题的解答的表达形式为:
    A: 9240k+9237,k=0,1,2,3,…
    B: 9240k-3,k=1,2,3,…
    C: 18480k+9237,k=0,1,2,3,…
    D: 18480k-3,k=1,2,3,…
    E: 18480k+18477,k=0,1,2,3,…
    F: 18480k-9243,k=1,2,3,…
    G: 9240k+18477,k=0,1,2,3,…
    H: 18480k+10557,k=0,1,2,3,…