A: 1 :
B: True :
C: True
D: 0
举一反三
- 使用while 语句实现打印出1至10.count = 1while ( ) print (count) count = count + 1 A: count B: True C: count D: count
- count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")
- 下列程序的运行结果是（ ）。 count = 0 while count < 5: print(count, " is less than 5") count = count + 1 else: print(count, " is not less than 5")
- 下列语句会陷入死循环的是_____. A: while True: break B: while 1<10: print("hello") C: while True: if 1<10: break D: while 1<10: break
- 请阅读下面的程序: count = 0 while count < 5: print(count, '小于5') if count == 2: break count += 1 else: print(count, "不小于5") 关于上述程序的说法中,描述错误的是
内容
- 0
The output of the following code is ____.<br/>count = 1; /* initialize count */ while (count <= 10) { printf("%d ",count); count++; /* increment count */ } A: 1 1 1 1 1 1 1 1 … B: 1 2 3 4 5 6 7 8 9 C: 1 2 3 4 5 6 7 8 9 10 D: 1 2 3 4 5 6 7 8 9 10 11
- 1
for(count = 1;sum=0; count <=10; count++)是正确的for语句
- 2
下列程序的输出结果是（） num = 27 count = 0 while num > 0: if num % 2 == 0: num /=2 elif num % 3 ==0: num /= 3 else: num -=1 count += 1 print (count)
- 3
使用for 语句把 Python 字符串的每个字母依次打印出来，下面哪个选项实现了（） A: count=1 for letter in Python: print（“Python的第"+str(count)+"个字母是”+letter） count=count+1 B: count=1 for letter "Python”: print（“Python的第"+str(count)+"个字母是”+letter） count=count+1 C: count=1 for letter in "Python": print（“Python的第"+str(count)+"个字母是”+letter） count=count+1
- 4
下面程序的运行结果是（）。#includeintmain(){inta,s,n,count;a=2;s=0;n=1;count=1;while(count<=7){n=n*a;s=s+n;++count;}printf(“%d”,s);return0;}