以下程序输出结果是( ) #include void sub ( double x,double *y ,double *z) {*y =*y -1.0;*z= *z +x;} main () {double a= 2.5, b= 9.0,*pa, *pb; pa= &a; pb =&b; sub ( b-a, pa,pa ); printf ("%f\n", a); }
A: 9.000000
B: 1.500000
C: 8.000000
D: 10.500000
A: 9.000000
B: 1.500000
C: 8.000000
D: 10.500000
举一反三
- 若有以下程序：#include <stdio.h>void sub (double x, double *y, double *z){ *y=*y-1.0; *z=*z+x; }main( ){ double a=2.5, b=9.0, *pa, *pb; pa=&a; pb=&b; sub ( b-a, pa, pa); printf(“%f\n”, a);}程序的输出结果是 A: 9.000000 B: 1.500000 C: 8.000000 D: 10.500000
- 若有以下程序： #include＜stdio.h＞ void sub(double x, double*y, double*z) { *y=*y-1.0; *z=*z+x; } main() {double a=2.5, b=9.0, *pa, *pb; pa=&a; pb=&b; sub(b-a, pa, pa); printf("%f\n", a); } 程序的输出结果是 A: 9.000000 B: 1.500000 C: 8.000000 D: 10.500000
- 以下程序的输出结果是____?double sub(double x,double y,double z){ y=-1; z=z+x; return z;}main(){ double a=2.5,b=9.0; printf("%f\n",sub(b-a,a,a));}
- 下列程序运行的结果是__________ 。#include <;stdio.h>;double sub(double x, double y, double z){y -= 1.0;z = z + x;return z;}int main( ){double a=2.5, b=9.0;printf("%6.2f\n", sub(b-a, a, a));return 0;}
- 有以下程序#include [stdio.h] void sub(double a,double *pb); int main(){ double x,y; scanf("%lf%lf",&x,&y); sub(x,&y); printf("x=%fy=%f\n",x,y); } void sub(double a,double *pb){ a=a-*pb; *pb=*pb-a; }程序运行时输入: 10.2 3.5[回车]，则输出结果为( )。 A: x=10.200000 y=-3.200000 B: x=6.700000 y=-13.700000 C: x=7.000000 y=-3.500000 D: x=13.400000 y=-7.000000