• 2022-06-09
    设矩阵[tex=8.571x3.643]QN0fTQbn6M33pU3gx/S2svsG3i64M1qCGgKjhApBlohSB4x3+dd95YZujYBJC3QNI/95hoiw33ZZWL/+AHcY/pJCDO4J2oK1g/ty6tKu80n+sXLw4pjV+JXrJgQ0c7oY[/tex],求正交矩阵[tex=0.857x1.214]bKYFB0pw9Vz5Wjasq5kxDA==[/tex],使[tex=3.286x1.429]hwtPsKLJq5x8Qu2B8wXGlA==[/tex]为对角矩阵.
  • 举一反三