写出下列程序的执行结果[color=#000000]#include <stdio.h> [/color][color=#000000]int main(void) [/color][color=#000000]{ [/color][color=#000000] int a[10], b[10], *pa, *pb, i; [/color][color=#000000] pa = a; [/color][color=#000000] pb = b; [/color][color=#000000] for( i=0; i<3; i++, pa++, pb++) [/color][color=#000000] { [/color][color=#000000] *pa = i; [/color][color=#000000] *pb = 2*i; [/color][color=#000000] printf(“%d\t%d\n”, *pa, *pb); [/color][color=#000000] } [/color][color=#000000] pa = &a[0]; [/color][color=#000000] pb = &b[0]; [/color][color=#000000] for ( i=0; i<3; i++) [/color][color=#000000] { [/color][color=#000000] *pa = *pa + i; [/color][color=#000000] *pb = *pb + i; [/color][color=#000000] printf(“%d\t%d\n”, *pa++, *pb++); [/color][color=#000000] } [/color][color=#000000][color=#000000] return 0; [/color][/color][color=#000000]} [/color]

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2022-06-09

写出下列程序的执行结果[color=#000000]#include <stdio.h> [/color][color=#000000]int main(void) [/color][color=#000000]{ [/color][color=#000000] int a[10], b[10], pa, pb, i; [/color][color=#000000] pa = a; [/color][color=#000000] pb = b; [/color][color=#000000] for( i=0; i<3; i++, pa++, pb++) [/color][color=#000000] { [/color][color=#000000] pa = i; [/color][color=#000000] pb = 2i; [/color][color=#000000] printf(“%d\t%d\n”, pa, pb); [/color][color=#000000] } [/color][color=#000000] pa = &a[0]; [/color][color=#000000] pb = &b[0]; [/color][color=#000000] for ( i=0; i<3; i++) [/color][color=#000000] { [/color][color=#000000] pa = pa + i; [/color][color=#000000] pb = pb + i; [/color][color=#000000] printf(“%d\t%d\n”, pa++, *pb++); [/color][color=#000000] } [/color][color=#000000][color=#000000] return 0; [/color][/color][color=#000000]} [/color]

写出下列程序的执行结果[color=#000000]#include [/color][color=#000000]int main(void) [/color][color=#000000]{ [/color][color=#000000] int a[10], b[10], *pa, *pb, i; [/color][color=#000000] pa = a; [/color][color=#000000] pb = b; [/color][color=#000000] for( i=0; i<3; i++, pa++, pb++) [/color][color=#000000] { [/color][color=#000000] *pa = i; [/color][color=#000000] *pb = 2*i; [/color][color=#000000] printf(“%d\t%d\n”, *pa, *pb); [/color][color=#000000] } [/color][color=#000000] pa = &a[0]; [/color][color=#000000] pb = &b[0]; [/color][color=#000000] for ( i=0; i<3; i++) [/color][color=#000000] { [/color][color=#000000] *pa = *pa + i; [/color][color=#000000] *pb = *pb + i; [/color][color=#000000] printf(“%d\t%d\n”, *pa++, *pb++); [/color][color=#000000] } [/color][color=#000000][color=#000000] return 0; [/color][/color][color=#000000]} [/color]

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