不能查询到所有姓“李"的学生信息的SQL命令是（ ）
A: SELECTsno,sname FROM studentInfo WHERE sname LIKE "李%";
B: SELECTsno,sname FROM studentInfo WHERE sname = "李";
C: SELECTsno,sname FROM studentInfoWHERE left(sname,1) = "李";
A: SELECTsno,sname FROM studentInfo WHERE sname LIKE "李%";
B: SELECTsno,sname FROM studentInfo WHERE sname = "李";
C: SELECTsno,sname FROM studentInfoWHERE left(sname,1) = "李";
举一反三
- 查询姓“李”的学生的所有信息 A: select * from student where sname like ‘#李%’ B: select * from student where sname like ‘%李#’ C: select * from student where sname like “%李%” D: select * from student where sname like ‘%李%
- 若要求查找‘李’姓学生的学生号和姓名,正确的SQL语句是( )。 A: SELECT S#,SNAME FROM S WHERE SNAME=’李%’ B: SELECT S#,SNAME FROM S WHERE SNAME LIKE ’李%’ C: SELECT S#,SNAME FROM S WHERE SNAME=’%李%’ D: SELECT S#,SNAME FROM S WHERE SNAME LIKE ’%李%’
- 查询学生表中，所有学生的学号（sno），姓名（sname），性别（sex），和生日（birthday），下列select语句正确的是 A: SELECTsno, sname, sex, birthday FROMstudent B: SELECT * FROM student C: SELECTsno, sname, birthday FROM student D: SELECTsno, sname, sex FROMstudent
- 假定有学生关系S，结构为S(SID, SNAME, AGE)，其中SID为学号，SNAME为姓名，AGE为年龄。查询所有比“李军”年龄大的学生的姓名、年龄，正确的SQL语句是（ ）。 A: SELECT SNAME, AGE FROM S WHERE AGE > ( SELECT AGE FROM S WHERE SNAME = '李军' ) B: SELECT SNAME, AGE FROM S WHERE AGE >( SNAME= '李军' ) C: SELECT SNAME, AGE FROM S WHERE AGE > ( SELECT AGE WHERE SNAME='李军' ) D: SELECT SNAME, AGE FROM S WHERE AGE>李军.AGE
- 查询姓"张"的学生姓名,下列()语句不能实现。 A: SELECT sname FROM student WHERE left(sname,1)= '张' B: SELECT snameFROM student WHERE sname LIKE '张%' C: SELECT sname FROM student WHERE substring(sname,1,1)= '张' D: SELECT sname FROM student WHERE sname='张%'