• 2022-06-07
    求不定积分[img=132x48]17da6537fc8dad6.png[/img]; ( )
    A: -(4*(cos(x/2)/2 + 2*sin(x/2)))/(17*exp(2*x))
    B: (4*(sin(x/2)/2 + 2*sin(x/2)))/(17*exp(2*x))
    C: (4*(cos(x/2)/2 + 2*sin(x/2)))/(17*exp(2*x))
    D: (4*(cos(x/2)/2 + 2*cos(x/2)))/(17*exp(2*x))
  • A

    举一反三

    内容

    • 0

      求微分方程 [img=635x61]17da6537085dd29.png[/img] 的特解; ( ) A: (3*sin(5*x))/exp(2*x) B: exp(2*x) C: (3*sin(5*x)) D: (3*cos(5*x))/exp(2*x)

    • 1

      $\int {{1 \over {3 + 5\cos x}}} dx = \left( {} \right)$ A: ${1 \over 4}\ln \left| {{{2\cos x + \sin x} \over {2\cos x - \sin x}}} \right| + C$ B: ${1 \over 4}\ln \left| {{{2\cos {x \over 2} + \sin {x \over 2}} \over {2\cos {x \over 2} - \sin {x \over 2}}}} \right| + C$ C: $\ln \left| {{{\cos {x \over 2} + \sin {x \over 2}} \over {\cos {x \over 2} - \sin {x \over 2}}}} \right| + C$ D: $\ln \left| {{{\cos x + \sin x} \over {\cos x - \sin x}}} \right| + C$

    • 2

      曲线积分$$\int_{(0,0}^{(x,y)}(2x\cos y-y^2\sin x)dx+(2y\cos x-x^2\sin y)dy=$$ A: $y^2\cos x+x^2\cos y$ B: $x^2\cos x+y^2\cos y$ C: $x^2\sin y+y^2\sin x$ D: $x^2\sin x+y^2\sin y$

    • 3

      求微分方程[img=634x60]17da653955cf9e7.png[/img]的特解。 ( ) A: sin(2*x)/3 - cos(x) - cos(x)/3 B: sin(2*x)/3 - cos(x) - sin(x)/3 C: cos(2*x)/3 - cos(x) - sin(x)/3 D: sin(2*x)/3 - sin(x) - sin(x)/3

    • 4

      函数[img=79x27]180355ae2690a03.png[/img]在x=2处的二阶泰勒展开式为 A: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 B: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2-cos(2)^2/2)*(x-2)^2 C: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)-exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2 D: exp(sin(2))+cos(2)*exp(sin(2))*(x-2)+exp(sin(2))*(sin(2)/2+cos(2)^2/2)*(x-2)^2