Where is David Carter?
举一反三
- 通过 SQL，按字母顺序选取 Actor 表中 LastName 介于 Adams 和 Carter 的所有记录的表述正确的是（ ）。? SELECT * FROM Actor WHERE LastName BETWEEN 'Adams' AND 'Carter'|SELECT LastName>'Adams' AND LastName<'Carter' FROM Actor|SELECT * FROM Actor WHERE LastName>'Adams' AND LastName<'Carter'|SELECT * FROM Actor WHERE LastName>'Adams' OR LastName<'Carter'
- 通过 SQL，在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是（ ）。? SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter'|SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'|SELECT FirstName='Jim', LastName='Carter' FROM Actor|SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter'
- 通过 SQL，按字母顺序选取 Actor 表中 LastName 介于 Adams 和 Carter 的所有记录的表述正确的是（ ）。 A: SELECT * FROM Actor WHERE LastName BETWEEN 'Adams' AND 'Carter' B: SELECT * FROM Actor WHERE LastName>'Adams' AND LastName<'Carter' C: SELECT LastName>'Adams' AND LastName<'Carter' FROM Actor D: SELECT * FROM Actor WHERE LastName>'Adams' OR LastName<'Carter'
- 通过 SQL，在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是（ ）。 A: SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter' B: SELECT FirstName='Jim', LastName='Carter' FROM Actor C: SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter' D: SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'
- 通过 SQL，按字母顺序选取 Actor 表中 LastName 介于 Adams 和 Carter 的所有记录的表述正确的是（ ）。 A: SELECT * FROM Actor WHERE LastName BETWEEN 'Adams' AND 'Carter' B: SELECT * FROM Actor WHERE LastName>'Adams' AND LastName<'Carter' C: SELECT LastName>'Adams' AND LastName<'Carter' FROM Actor D: SELECT * FROM Actor WHERE LastName>'Adams' OR LastName<'Carter'