举一反三
- 如果检查过程中没有发现损伤，则装配组件。 A: If you do not find damage during the inspection procedure, assemble the unit. B: If you do not discover damage during the inspection procedure, assemble the unit. C: If the inspection does not encounter any damage, assemble the unit. D: If the inspection does not evidence any damage, assemble the unit.
- 30.The company is making a large profit, but at the same time they (do)____a lot of damage to the environment.
- MATLAB符号工具箱中求极限函数是LIMIT ，下面的调用格式中，其中正确的有（ ）个 1、LIMIT(F,x，a) 2、LIMIT(F,a) 3、LIMIT(F) 4、LIMIT(F,x,a,‘right’) 5、LIMIT(F,x,a,‘left’) A: 2 B: 3 C: 4 D: 5
- The passage mainly aims to identify that nanotech may do potential damage to our health and environment.
- 9．Alcohol is classified as a downer，and although it is legal，it can damage the liver and do great harm if ______ in large quantities.
内容
- 0
计算的命令错误的是（ ）。 A: syms x; limit((sqrt(x^2+1)-3*x)/(x+sin(x)),x,inf) B: syms x; limit((sqrt(x^2+1)-3*x)/(x+sin(x)),Inf) C: syms x; limit((sqrt(x^2+1)-3*x)/(x+sin(x)),inf) D: syms x; limit((sqrt(x^2+1)-3*x)/(x+sin(x)))
- 1
I do apologize for_____you so much trouble. A: damage B: damaging C: causing D: cause
- 2
在Matlab中求[img=123x44]18030b2956167b1.png[/img]极限的命令是（ ） A: syms x; limit(‘(tanx-sinx)/sin2x^3’,x,0) B: syms x; limit(‘(tanx-sinx)/(sin2x)^3’,x,0) C: syms x; limit(‘(tan(x)-sin(x))/(sin(2*x))^3’,x,0) D: syms x; limit(‘(tan(x)-sin(x))/(sin2x)^3’,x,0)
- 3
17da555a3275fb2.png,计算极限的实验命令为(). A: limit((x-sin(x))/x^3,x,0)ans =1/2 B: syms x; limit((x-sin(x))/(x.^3),x,0)ans =1/6 C: syms x; limit(x-sinx)/x^3,x,0)ans =1/6
- 4
实验命令“syms x y a, limit(limit(sin(x*y^3)/(x*y^2),x,0),y,a)”的结果为【】.