两简支梁的材料、截面形状及梁中点承受的集中载荷均相同,而两梁的跨度L1/ L2=1/2,则其最大挠度之比为
A: y1max/ y2max=1/2
B: y1max/ y2max=1/4
C: y1max/ y2max=1/6
D: y1max/ y2max=1/8
A: y1max/ y2max=1/2
B: y1max/ y2max=1/4
C: y1max/ y2max=1/6
D: y1max/ y2max=1/8
举一反三
- 已知x=1,2y=3,4z=(x,y)下列哪个表达式的值为4 A: max(z) B: max(max(z)) C: z[2][2] D: z[-1][-1]
- 10、以下程序的运行结果是( )#include <;stdio.h>;void main(){ int a=1,b=2,c;c=max(a,b);printf(“max is %d\n”,c);}max(int x, int y){ int z;z=(x>;y)? x:y;return(z);} A: max is 2 B: max is 1 C: max is 3 D: max is 12
- #include "stdio.h" int main() { int x,y, (1) ; scanf("%d%d%d", &x,&y,&z); if(x>=y) (2) ; (3) max=y; if( (4) ) max=z; printf("%d\n",max); }
- 以下代码段中正确的是( ) A: int a=8;if(a>=1) a = b + 1; B: int x=6,y=9,max;if(x>y) max=x; C: int x;scanf("%d",&x);switch(x>90&&x<=100){ case '2' : case '97' : case x>y : default :} D: int x=7,y=10,max;if(x>y) ; max=x;else max=y;
- 设x=24,y=36表达式max=x>y?x:y返回值是( ) A: max=24 B: max=36 C: max=0 D: max=1