He was a tough __________ in debate. A: ival B: opponent C: person
He was a tough __________ in debate. A: ival B: opponent C: person
下面代码暴露了一个常见编程错误。请指出并修改之。 int ival=512, jval=1024, kval=4096; int bufsize;//...switch(swt){ case ival: bufsize=ival* sizeof(int); break; case jval: bufsize=jval * sizeof(int); break; case kval: bufsize=kval * sizeof(int); break; }
下面代码暴露了一个常见编程错误。请指出并修改之。 int ival=512, jval=1024, kval=4096; int bufsize;//...switch(swt){ case ival: bufsize=ival* sizeof(int); break; case jval: bufsize=jval * sizeof(int); break; case kval: bufsize=kval * sizeof(int); break; }
生成: 6 7 8 6 7 8 6 7 8
生成: 6 7 8 6 7 8 6 7 8
若将文本字符串"15"、"8"、"6"按降序排序，则排序的结果为（） A: "15"、"8"、"6" B: "6"、"8"、"15" C: "8"、"6"、"15" D: "8"、"15"、"6\
若将文本字符串"15"、"8"、"6"按降序排序，则排序的结果为（） A: "15"、"8"、"6" B: "6"、"8"、"15" C: "8"、"6"、"15" D: "8"、"15"、"6\
该String str = 6 > 8 ?”6不大于8”: “6小于8”; System.out.println(str); 输出结果是
该String str = 6 > 8 ?”6不大于8”: “6小于8”; System.out.println(str); 输出结果是
In a football team, a _______ is also a vital member. A: docto B: eferee C: goal D: ival
In a football team, a _______ is also a vital member. A: docto B: eferee C: goal D: ival
People are surprised to learn that the so-called “liberals” are not in ____ of freedom. A: ival B: favo C: facto D: vessel
People are surprised to learn that the so-called “liberals” are not in ____ of freedom. A: ival B: favo C: facto D: vessel
The firm has drawn up a _________ for the coming year. A: company B: ival C: udget D: picture
The firm has drawn up a _________ for the coming year. A: company B: ival C: udget D: picture
以下属于基差走强的有（ ） A: -8变为-6 B: 8变为6 C: 8变为-6 D: -8变为-10
以下属于基差走强的有（ ） A: -8变为-6 B: 8变为6 C: 8变为-6 D: -8变为-10
若整型变量a和b的值分别为６和８，则下列语句printf("a=%d,b=%d",a,b); 的输出结果为( )。 A: 6, 8 B: 6 8 C: a=6 b=8 D: a=6, b=8
若整型变量a和b的值分别为６和８，则下列语句printf("a=%d,b=%d",a,b); 的输出结果为( )。 A: 6, 8 B: 6 8 C: a=6 b=8 D: a=6, b=8