下面()不是有效的变量名 A: _score B: "banana" C: Number D: my_score

My new doctor is a __________. A: normal B: behaviorist C: freshman D: score

My new doctor is a __________.(1.0) A: normal B: behaviorist C: freshman D: score

VII. Sentence Translation: Translate the following sentences into Chinese. (2*5) 10%1. I no longer blame my parents for my every personality quirk or keep a running score of everything they did wrong raising me.

下面代码的输出结果是()。 <?php $score=87; if($score>=90 && $score<=100){$grade="优秀";} if($score>=80){$grade="良好";} if($score>=70){$grade="一般";} if($score>=60){$grade="及格";} else{$grade="不及格";} echo $grade; ?>

以下参数传递正确的是： A: def score(mid_score, end_score): ……score(88, 79) B: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(88, 79) C: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(end_score = 79, mid_score = 88) D: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(mid_score = 88, end_score = 79,0.5)

There are ________students playing basketball in the room. A: score of B: scores of C: two score D: two score of

若有定义int score&#91;10&#93;;，则对score数组中的元素的正确引用是（ ） A: score[10] B: score[6.0] C: score[0] D: score(7)

从学生成绩表SC中查询平均成绩大于60分的同学的学号和平均成绩的正确语句为： A: selectsno,avg(score)assscorefromscgroupbysnohavingavg(score)>60 B: selectsno,avg(score)assscorefromscgroupbysnowhereavg(score)>60 C: selectsno,avg(score)assscorefromscwhereavg(score)>60 D: selectsno,avg(score)assscorefromschavingavg(score)>60

查询成绩在60-80之间的学生信息，正确的语句是？ A: db.students.find({"score":{$gte:60,$lte:80}}) B: db.students.find({"score":{$gte:80},{"score":{$lte:60}}}) C: db.students.find({"score":{$gte:60},{"score":{$te:80}}}) D: db.students.find({"score":{$gt:80},{"score":{$lt:60}}})