The replicated study done by Chen and Yang revealed similar findings as Chen’s 1993 study.

Chen Lin: Good morning. You [1] ______ be Mr Lohmann. Martin: Yes, that’s right. Chen Lin: I’m Chen Lin, Mr Li’s personal [2]________. How do you do?

17.Excuse me, but could you tell me ______ telephone number? I’ve forgotten ______. A: Comrade Chen’s… his B: Comrade Chen…his C: Comrade Chen’s… him D: Comrade Chens’… hers

Which one is not the suggestion given by Professor Chen for non-English majors who want to have a better understanding of English literature?</p></p>

Ryran refuses to appoint Chen Yun's company as his company's agent because Chen Yun's company _____. A: lacks business experience in the needed line B: is not willing to promise a minimum annual sales C: has no good business connections with sellers of different levels D: is not familiar with customers' needs

在循环双链表的p结点之后插入s结点的操作是______。 A: p→next=s；p→next→prior=s；S→prior=p；S→next=p→next； B: s→next=p；s→next=p→next；p→next=s；p→next→prior=s； C: p→next=s；s→prior=p；p→next→prior=s；s→next=p→next； D: s→prior=p；s→next=p→next；p→next→prior=s；p→next=S；

在循环双链表的p所指结点之后插入s所指结点的操作是() A: P—＞next=s； B: p—＞next=s；s—＞prior=p；p—＞next—＞prior=s；p—＞next—＞prior=s；s—＞prior=p；s—＞next=p—＞next；s—＞next=p—＞next C: s—＞prior=p； D: s—＞prior=p；s—＞next=p—＞next；s—＞next=p—＞next；p—＞next=s；p—＞next—＞prior=s；p—＞next—＞prior=s；p—＞next=s；

完成在双循环链表结点p之后插入s的操作是()A.()p->next=s();()s()->()prior=p;()p()->()next()->()prior=s();()s()->()next=p()->()next;()B.()p()->()next()->()prior=s;()p()->()next=s;()s()->()prior=p;()s()->()next=p()->()next;()C.()s()->()prior=p;()s()->()next=p()->()next;()p()->()next=s;()p()->()next()->()prior=s();()D.()s()->()prior=p;()s()->()next=p()->()next;()p()->()next()->()prior=s();()p()->()next=s;

Chen Daming can also be written as “Daming Chen”.

【单选题】在循环双链表的 p 所指结点之后插入 s 所指结点的操作是 () 。 A. p à right =s ； s à left = p ； p à right à left = s ； s à right = p à right ； B. p à right =s ； p à right à left = s ； s à left = p ； s à right = p à right； C. s à left = p ； s à right = p à right ； p à right = s ； p à right à left = s； D. s à left = p ； s à right = p à right ； p à right à left = s ； p à right = s ；