• 2022-06-16 问题

    类MyClass的定义如下: class MyClass { int value; public: MyClass(){value=0;} SetVariable(int i){value=i;} }; MyClass *p, my; p=&my; 则下列描述正确的是( ) A: 语句p=&my;是把对象my赋值给指针变量p B: 语句MyClass *p,my;会调用两次类MyClass的构造函数 C: 对语句*p.SetVariable(5)的调用是正确的 D: 语句p->SetVariable(5);与语句my.SetVariable(5);等价

    类MyClass的定义如下: class MyClass { int value; public: MyClass(){value=0;} SetVariable(int i){value=i;} }; MyClass *p, my; p=&my; 则下列描述正确的是( ) A: 语句p=&my;是把对象my赋值给指针变量p B: 语句MyClass *p,my;会调用两次类MyClass的构造函数 C: 对语句*p.SetVariable(5)的调用是正确的 D: 语句p->SetVariable(5);与语句my.SetVariable(5);等价

  • 2022-06-16 问题

    类MyClass的定义如下: class MyClass public: MyClass()value=0; SetVariable(int i)value=i; private: int value; ; 则对下列语句序列正确的描述是( )。 A: 语句p=&my;是把对象my赋值给指针变量p B: 语句MyClass *p,my;会调用两次类MyClass的构造函数 C: 对语句*p.SetVariable(5)的调用是正确的 D: 语句p->SetVariable(5)与语句my.SetVariable(5)等价

    类MyClass的定义如下: class MyClass public: MyClass()value=0; SetVariable(int i)value=i; private: int value; ; 则对下列语句序列正确的描述是( )。 A: 语句p=&my;是把对象my赋值给指针变量p B: 语句MyClass *p,my;会调用两次类MyClass的构造函数 C: 对语句*p.SetVariable(5)的调用是正确的 D: 语句p->SetVariable(5)与语句my.SetVariable(5)等价

  • 2021-04-14 问题

    类MyClass的定义如下: class MyClass { public: MyClass(){value=0;} SetVariable(int i){value=i;) private: int value; }; 则对下列语句序列正确的描述是( )。 A.MyClass*p,my;p=&my; B.语句p=&my;是把对象my赋值给指针变量p C.语句MyClass*p,my;会调用两次类MyClass的构造函数 D.对语句*p.SetV ariable(5)与语句my.SetVariable(5)等价

    类MyClass的定义如下: class MyClass { public: MyClass(){value=0;} SetVariable(int i){value=i;) private: int value; }; 则对下列语句序列正确的描述是( )。 A.MyClass*p,my;p=&my; B.语句p=&my;是把对象my赋值给指针变量p C.语句MyClass*p,my;会调用两次类MyClass的构造函数 D.对语句*p.SetV ariable(5)与语句my.SetVariable(5)等价

  • 2022-06-16 问题

    类MyClass的定义如下: class MyClass { public: MyClass(){value=0;} SetVariable(int i){value=i;} private: int value; }; 则对下列语句序列正确的描述是( )。 A: 语句p=&my,是把对象:my赋值给指针变量p B: 语句MyClass*p,my;会调用两次类MyClass的构造函数 C: 对语句*SetVariable(5)的调用是正确的 D: 语句P->SetVariable(5)与语句mSetVariable(5)等价

    类MyClass的定义如下: class MyClass { public: MyClass(){value=0;} SetVariable(int i){value=i;} private: int value; }; 则对下列语句序列正确的描述是( )。 A: 语句p=&my,是把对象:my赋值给指针变量p B: 语句MyClass*p,my;会调用两次类MyClass的构造函数 C: 对语句*SetVariable(5)的调用是正确的 D: 语句P->SetVariable(5)与语句mSetVariable(5)等价

  • 2021-04-14 问题

    类MyClass的定义如下: class MyClass { public: MyClass(){ value = 0;} SetVariable(inti) { value = i; } private: int value; } 则对下列语句序列:MyClass*p,my; p=&my;正确的描述是( )。

    类MyClass的定义如下: class MyClass { public: MyClass(){ value = 0;} SetVariable(inti) { value = i; } private: int value; } 则对下列语句序列:MyClass*p,my; p=&my;正确的描述是( )。

  • 2022-06-16 问题

    类MyClass的定义如下: class MyClass { int value; public: MyClass(){value=0;} SetVariable(int i){value=i;} }; 则对下列语句序列正确的描述是( )。 MyClass *p, my; p=&my;

    类MyClass的定义如下: class MyClass { int value; public: MyClass(){value=0;} SetVariable(int i){value=i;} }; 则对下列语句序列正确的描述是( )。 MyClass *p, my; p=&my;

  • 2022-06-06 问题

    My mother a doctor is my father so is A: My mother is a doctor. So is my father B: My mother is a doctor. So my father is C: My mother is a doctor. My father is so.

    My mother a doctor is my father so is A: My mother is a doctor. So is my father B: My mother is a doctor. So my father is C: My mother is a doctor. My father is so.

  • 2022-06-06 问题

    Jack, a friend of ________, often comes to see us. A: my brother and my sister B: my brother’s and my sister C: my brother and my sister’s D: my brother’s and my sister’s

    Jack, a friend of ________, often comes to see us. A: my brother and my sister B: my brother’s and my sister C: my brother and my sister’s D: my brother’s and my sister’s

  • 2022-06-06 问题

    I had supper with my _________that evening. A: my father B: my mother C: my brother D: my grandpa

    I had supper with my _________that evening. A: my father B: my mother C: my brother D: my grandpa

  • 2022-06-15 问题

    以下表达式中,正确的是( ) A: K'(MY) = c(MY) / c(M)c(Y) B: K'(MY) = [MY] / [M][Y] C: K(MY) = [MY]/ [M][Y] D: K(MY) = [M][Y]/ [MY]

    以下表达式中,正确的是( ) A: K'(MY) = c(MY) / c(M)c(Y) B: K'(MY) = [MY] / [M][Y] C: K(MY) = [MY]/ [M][Y] D: K(MY) = [M][Y]/ [MY]

  • 1 2 3 4 5 6 7 8 9 10