• 2022-06-07 问题

    David is not driving my car but __________ . A: someone elses B: someone else's

    David is not driving my car but __________ . A: someone elses B: someone else's

  • 2021-04-14 问题

    中国大学MOOC: We don’t want to profit from someone elses ____________.

    中国大学MOOC: We don’t want to profit from someone elses ____________.

  • 2022-06-06 问题

    He was not driving Charle’s car but someone elses’.(Improve the sentence where necessary.)

    He was not driving Charle’s car but someone elses’.(Improve the sentence where necessary.)

  • 2022-05-27 问题

    inti=5,s=0;do{if(i%2)continue;elses+=i;}while(--i);程序段执行后s的值为:

    inti=5,s=0;do{if(i%2)continue;elses+=i;}while(--i);程序段执行后s的值为:

  • 2022-06-12 问题

    以下程序的运行结果是_________。#include "stdio.h"void main(){int m=1,s=1;do{++m;if(m%3!=0)continue;elses=s*m;printf("%d\n",s);}while(m<10);}

    以下程序的运行结果是_________。#include "stdio.h"void main(){int m=1,s=1;do{++m;if(m%3!=0)continue;elses=s*m;printf("%d\n",s);}while(m<10);}

  • 2022-06-12 问题

    下面程序的输出是____。long fun5(int n){long s;if((n==1)||(n==2))s=2;elses=n+fun5(n-1);return(s);}main(){long x;x=fun5(4);printf("%ld\n",x);}

    下面程序的输出是____。long fun5(int n){long s;if((n==1)||(n==2))s=2;elses=n+fun5(n-1);return(s);}main(){long x;x=fun5(4);printf("%ld\n",x);}

  • 2022-06-12 问题

    读程序并写结果。#include stdio.hlong fun(int n){ long s;if(n==1||n==2)s=2;elses=n-fun(n-1);return s;}int main(){ printf(%ld\n,fun(3)); return 0;}

    读程序并写结果。#include stdio.hlong fun(int n){ long s;if(n==1||n==2)s=2;elses=n-fun(n-1);return s;}int main(){ printf(%ld\n,fun(3)); return 0;}

  • 2022-06-09 问题

    3.11下面()语句与下列if语句等价。if(a>;b) s=a+b;elses=a-b; A: switch(a>;b) { case 1:s=a+b;break; case 0:s=a-b;break; } B: switch(a>;b) { case 1:s=a+b; case 0:s=a-b; } C: switch(a<;b) { case 1:s=a-b; case 0:s=a+b; } D: switch(a<;b) { case 1:s=a-b;break; case 0:s=a+b;break; }

    3.11下面()语句与下列if语句等价。if(a>;b) s=a+b;elses=a-b; A: switch(a>;b) { case 1:s=a+b;break; case 0:s=a-b;break; } B: switch(a>;b) { case 1:s=a+b; case 0:s=a-b; } C: switch(a<;b) { case 1:s=a-b; case 0:s=a+b; } D: switch(a<;b) { case 1:s=a-b;break; case 0:s=a+b;break; }

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