• 2021-04-14 问题

    根据下表回答问题: 基变量 c b x1 x2 s1 s2 s3 b 比值 Bi/ai2 50 100 0 0 0 () () () 1 1 1 0 0 2 1 0 1 0 0 1 0 0 1 300 400 250 300/1 400/1 250/1 zj σ 0 0 0 0 0 50 100 0 0 0 z=0 入基变量为( )

    根据下表回答问题: 基变量 c b x1 x2 s1 s2 s3 b 比值 Bi/ai2 50 100 0 0 0 () () () 1 1 1 0 0 2 1 0 1 0 0 1 0 0 1 300 400 250 300/1 400/1 250/1 zj σ 0 0 0 0 0 50 100 0 0 0 z=0 入基变量为( )

  • 2022-06-09 问题

    如图所示单元体的三个主应力为 A: σ1=30,σ2=0,σ3=-50 B: σ1=50,σ2=30,σ3=-50 C: σ1=50,σ2=0,σ3=-50 D: σ1=50,σ2=30,σ3=0

    如图所示单元体的三个主应力为 A: σ1=30,σ2=0,σ3=-50 B: σ1=50,σ2=30,σ3=-50 C: σ1=50,σ2=0,σ3=-50 D: σ1=50,σ2=30,σ3=0

  • 2022-06-09 问题

    图示应力状态的主应力σ1,σ2,σ3的值为( )[img=104x96]180347ed2b155b8.png[/img] A: σ1=50,σ2=50,σ3= -50 B: σ1=50,σ2=50,σ3=50 C: σ1=50,σ2=50,σ3=0 D: σ1=50,σ2=0,σ3=0

    图示应力状态的主应力σ1,σ2,σ3的值为( )[img=104x96]180347ed2b155b8.png[/img] A: σ1=50,σ2=50,σ3= -50 B: σ1=50,σ2=50,σ3=50 C: σ1=50,σ2=50,σ3=0 D: σ1=50,σ2=0,σ3=0

  • 2022-06-09 问题

    如图所示单元体的三个主应力为[img=199x211]17869506173a409.jpg[/img] A: σ1=30,σ2=0, σ3=-50 B: σ1=50,σ2=30, σ3=-50 C: σ1=50,σ2=0, σ3=-50 D: σ1=50,σ2=30, σ3=0

    如图所示单元体的三个主应力为[img=199x211]17869506173a409.jpg[/img] A: σ1=30,σ2=0, σ3=-50 B: σ1=50,σ2=30, σ3=-50 C: σ1=50,σ2=0, σ3=-50 D: σ1=50,σ2=30, σ3=0

  • 2022-06-09 问题

    如图所示单元体的三个主应力为[img=199x211]17da68e5a3a1ffa.jpg[/img] A: σ1=50,σ2=0, σ3=-50 B: σ1=30,σ2=0, σ3=-50 C: σ1=50,σ2=30, σ3=-50 D: σ1=50,σ2=30, σ3=0

    如图所示单元体的三个主应力为[img=199x211]17da68e5a3a1ffa.jpg[/img] A: σ1=50,σ2=0, σ3=-50 B: σ1=30,σ2=0, σ3=-50 C: σ1=50,σ2=30, σ3=-50 D: σ1=50,σ2=30, σ3=0

  • 2022-06-19 问题

    ‍对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码,结果是( )。‌ A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1

    ‍对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码,结果是( )。‌ A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1

  • 2021-04-14 问题

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]]

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]]

  • 2022-06-16 问题

    以下HDB3码中,哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……

    以下HDB3码中,哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……

  • 2021-04-14 问题

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]] 提示:可以先创建全为0或者全为1的数组,再通过索引和切片机制进行修改

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]] 提示:可以先创建全为0或者全为1的数组,再通过索引和切片机制进行修改

  • 2022-06-16 问题

    对信码1000100100001000011000011进行HDB3编码,结果可能是( )。 A: -1 0 0 0 +1 0 0 -1 0 0 0 -V +1 0 0 0 +V -1 +1 -B 0 0 -V +1 -1 B: +1 0 0 0 -1 0 0 +1 0 0 0 +V -1 0 0 0 -V +1 -1 +B 0 0 +V -1 +1 C: +1 0 0 0 -1 0 0 +1 0 0 0 +1 -1 0 0 0 -1 +1 -1 +1 0 0 +1 -1 +1 D: -1 0 0 0 +1 0 0 -1 0 0 0 +V +1 0 0 0 +V -1 +1 +B 0 0 -V +1 -1

    对信码1000100100001000011000011进行HDB3编码,结果可能是( )。 A: -1 0 0 0 +1 0 0 -1 0 0 0 -V +1 0 0 0 +V -1 +1 -B 0 0 -V +1 -1 B: +1 0 0 0 -1 0 0 +1 0 0 0 +V -1 0 0 0 -V +1 -1 +B 0 0 +V -1 +1 C: +1 0 0 0 -1 0 0 +1 0 0 0 +1 -1 0 0 0 -1 +1 -1 +1 0 0 +1 -1 +1 D: -1 0 0 0 +1 0 0 -1 0 0 0 +V +1 0 0 0 +V -1 +1 +B 0 0 -V +1 -1

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