\(二次型f（x）=x^{T}\begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{bmatrix}x的秩为\)

Simplify the expression:$({\frac{3x^{3/2}y^3}{x^2y^{-1/2}})^{-2}}$Which answer is CORRECT? A: $9xy^7$ B: $\frac19 xy^{-7}$ C: $\frac19 x^{-1}y^7$ D: $9 x^{-1}y^7$

设int a=9,b=8,c=7,x=1; ,则执行语句 if(a>7)if（b>8）if(c>9)x=2;else x=3;后x的值是（ ）。

设int a = 9,b = 8,c = 7, x = 1;则执行语句后x的值是: if (a>7) if (b>8) if (c>9) x=2 ; else x = 3；

已知函数定义def demo(a=1,**b):return b则demo(2,x=7,y=8,z=9)的返回值是什么? A: 2 B: (x:7,y:8,z:9) C: (7, 8, 9) D: {'x':7, 'y':8, 'z':9}

【单选题】设全集U={x|-7≤x≤7},A={x|-1≤x4},B={x|-2≤x≤3},Cu(A∪B)= A. ｛x|-7≤x≤-1｝ B. ｛x|-7≤x≤-1或3＜x≤7｝ C. ｛x|-7≤x＜2或4≤x≤7｝ D. ｛4≤x≤7｝

以4，9，1为为插值节点，求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)

设集合S＝{x|x>－2}，T＝{x|x2＋3x－4≤0}，则(?RS)∪T等于(　　)． A: (－2,1] B: (－∞，－4] C: (－∞，1] D: [1，＋∞)

set1 = {x for x in range(10) if x%2!=0} set1.remove(1) print(set1) 以上代码的运行结果为？ A: {1, 3, 5, 7, 9} B: {1, 3, 5, 7} C: {3, 5, 7, 9} D: {3, 5, 7}

set1 = {x for x in range(10) if x%2!=0} print(set1) 以上代码的运行结果为？ A: {1, 3, 5, 7, 9} B: {1, 3, 5, 7} C: {3, 5, 7, 9} D: {3, 5, 7}