• 2021-04-14 问题

    【填空题】Whynot dress in style and 3._____yourself in a large sweater?

    【填空题】Whynot dress in style and 3._____yourself in a large sweater?

  • 2022-06-05 问题

    A:Everybodyisgoingtoclimbthemountain.CanIgotoo,Mom?B:________Waittillyouareoldenough,dear. A: Willyou? B: Whynot? C: Ihopeso. D: I’mafraidnot.

    A:Everybodyisgoingtoclimbthemountain.CanIgotoo,Mom?B:________Waittillyouareoldenough,dear. A: Willyou? B: Whynot? C: Ihopeso. D: I’mafraidnot.

  • 2022-06-05 问题

    —Wouldyouliketogoforapicnicwithus?—_____,butI’mtoobusy. A: No,Ican’t B: Yes,Iwould C: I’dloveto D: Whynot

    —Wouldyouliketogoforapicnicwithus?—_____,butI’mtoobusy. A: No,Ican’t B: Yes,Iwould C: I’dloveto D: Whynot

  • 2021-04-14 问题

    The"OK"gesturemeans"OK"worldwide.

    The"OK"gesturemeans"OK"worldwide.

  • 2022-06-09 问题

    print('I\'m \"OK\"! ' )的输出结果是? A: I'm "OK"! B: I'm "OK"!' C: I'm 'OK'! D: I\'m "OK"!

    print('I\'m \"OK\"! ' )的输出结果是? A: I'm "OK"! B: I'm "OK"!' C: I'm 'OK'! D: I\'m "OK"!

  • 2022-06-16 问题

    以下程序的运行结果是【 A: OK B: OK,* C: OK* D: O,K

    以下程序的运行结果是【 A: OK B: OK,* C: OK* D: O,K

  • 2021-04-14 问题

    Idioms are _______for an informal letter. A. OK B. Not OK

    Idioms are _______for an informal letter. A. OK B. Not OK

  • 2021-04-14 问题

    若有定义语句char s1[]='OK',s2[]='ok';,以下选项中能够输出'OK'的语句是__________。

    若有定义语句char s1[]='OK',s2[]='ok';,以下选项中能够输出'OK'的语句是__________。

  • 2022-06-30 问题

    下列符合c语法的if语句是: A: if 3>5 then printf("Ok!"); B: if 3>5 printf("Ok!") C: if (3>5) then printf("Ok!"); D: if (3>5) printf("Ok!");

    下列符合c语法的if语句是: A: if 3>5 then printf("Ok!"); B: if 3>5 printf("Ok!") C: if (3>5) then printf("Ok!"); D: if (3>5) printf("Ok!");

  • 2022-06-29 问题

    想要使用while循环重复打印3次OK,下列代码正确的是? A: a = 0while a < 3: a += 1 print('OK') B: a = 0while a < 10: a += 1 print('OK') C: a = 0while a < 3: a += 1print('OK') D: a = 0while a < 3: print('OK')

    想要使用while循环重复打印3次OK,下列代码正确的是? A: a = 0while a < 3: a += 1 print('OK') B: a = 0while a < 10: a += 1 print('OK') C: a = 0while a < 3: a += 1print('OK') D: a = 0while a < 3: print('OK')

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