Consider the following cryptosystem: K={A, B}, Pr(A)=2/3, Pr(B)=1/3; P={0, 1}, Pr(0)=3/5, Pr(1)=2/5; C={a, b}, EA(0)=a, EA(1)=b, EB(0)=b, EB(1)=a; Compute Pr(a)=_______ and Pr(0|a)=_________;
Consider the following cryptosystem: K={A, B}, Pr(A)=2/3, Pr(B)=1/3; P={0, 1}, Pr(0)=3/5, Pr(1)=2/5; C={a, b}, EA(0)=a, EA(1)=b, EB(0)=b, EB(1)=a; Compute Pr(a)=_______ and Pr(0|a)=_________;
相关系数的检验假设是() A: Aρ=0 B: Bπ=0 C: Cμ=0 D: Dr=0 E: Eb=0
相关系数的检验假设是() A: Aρ=0 B: Bπ=0 C: Cμ=0 D: Dr=0 E: Eb=0
1⊙1⊙1⊙1⊙0⊙0⊙0⊙0等于?() A: 0⊙0⊙0⊙1 B: 1⊕1⊕1⊕1 C: 1⊙0⊙0⊙1 D: 1⊕1⊙0⊙0
1⊙1⊙1⊙1⊙0⊙0⊙0⊙0等于?() A: 0⊙0⊙0⊙1 B: 1⊕1⊕1⊕1 C: 1⊙0⊙0⊙1 D: 1⊕1⊙0⊙0
若逻辑表达式,则A、B、C、D分别为()。 A: 1、0、0、0 B: 0、1、0、0 C: 0、1、1、0 D: 1、0、1、1
若逻辑表达式,则A、B、C、D分别为()。 A: 1、0、0、0 B: 0、1、0、0 C: 0、1、1、0 D: 1、0、1、1
在差别定价的条件下,如果A市场的价格高于B市场,并且用Ea和Eb表示A市场和B市场的需求弹性,则 A: Ea>Eb B: Ea〈Eb C: Ea>Eb Ea=Eb=-1 D: Ea=Eb=0
在差别定价的条件下,如果A市场的价格高于B市场,并且用Ea和Eb表示A市场和B市场的需求弹性,则 A: Ea>Eb B: Ea〈Eb C: Ea>Eb Ea=Eb=-1 D: Ea=Eb=0
对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码,结果是( )。 A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1
对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码,结果是( )。 A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1
以下HDB3码中,哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……
以下HDB3码中,哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……
对信码1000100100001000011000011进行HDB3编码,结果可能是( )。 A: -1 0 0 0 +1 0 0 -1 0 0 0 -V +1 0 0 0 +V -1 +1 -B 0 0 -V +1 -1 B: +1 0 0 0 -1 0 0 +1 0 0 0 +V -1 0 0 0 -V +1 -1 +B 0 0 +V -1 +1 C: +1 0 0 0 -1 0 0 +1 0 0 0 +1 -1 0 0 0 -1 +1 -1 +1 0 0 +1 -1 +1 D: -1 0 0 0 +1 0 0 -1 0 0 0 +V +1 0 0 0 +V -1 +1 +B 0 0 -V +1 -1
对信码1000100100001000011000011进行HDB3编码,结果可能是( )。 A: -1 0 0 0 +1 0 0 -1 0 0 0 -V +1 0 0 0 +V -1 +1 -B 0 0 -V +1 -1 B: +1 0 0 0 -1 0 0 +1 0 0 0 +V -1 0 0 0 -V +1 -1 +B 0 0 +V -1 +1 C: +1 0 0 0 -1 0 0 +1 0 0 0 +1 -1 0 0 0 -1 +1 -1 +1 0 0 +1 -1 +1 D: -1 0 0 0 +1 0 0 -1 0 0 0 +V +1 0 0 0 +V -1 +1 +B 0 0 -V +1 -1
已知逻辑函数式为 F = A B + B C,可列出真值表如表2中的是( ) A B C ① ② ③ ④ 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 0 0 0 0 1 0 1 0 0 1 1 0 1 1 0 1 0 0 0 0 0 1 0 0 0 0 0 1 1 0 1 1
已知逻辑函数式为 F = A B + B C,可列出真值表如表2中的是( ) A B C ① ② ③ ④ 0 0 0 0 0 1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1 0 0 0 0 1 0 1 0 0 1 1 0 1 1 0 1 0 0 0 0 0 1 0 0 0 0 0 1 1 0 1 1
执行eye(3,5)后,其结果是( ) A: ans = <br> 1 0 0 0 1 0 0 0 1 B: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 C: ans = <br> 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 D: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0
执行eye(3,5)后,其结果是( ) A: ans = <br> 1 0 0 0 1 0 0 0 1 B: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 C: ans = <br> 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 D: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0