• 2021-04-14 问题

    【单选题】下列是日期型常量的一项是 A. "02/03/2020" B. 02/03/2020 C. {02/03/2020} D. #02/03/2020#

    【单选题】下列是日期型常量的一项是 A. "02/03/2020" B. 02/03/2020 C. {02/03/2020} D. #02/03/2020#

  • 2021-04-14 问题

    【单选题】?{^2020-03-06}+20 A. 03/16/20 B. 03/26/20 C. 06/26/20 D. 20/26/03

    【单选题】?{^2020-03-06}+20 A. 03/16/20 B. 03/26/20 C. 06/26/20 D. 20/26/03

  • 2022-06-18 问题

    ?CTOD(’03/14/08’)的值应为(). A: {03/14/08} B: 03/14/08 C: ″08-03-14″ D: 2008年3月14日

    ?CTOD(’03/14/08’)的值应为(). A: {03/14/08} B: 03/14/08 C: ″08-03-14″ D: 2008年3月14日

  • 2022-06-05 问题

    以下哪个不是Android手机常见的应用程序?( ) A: \data\data\com.tencent.mm B: \data\data\com.tencent.mobileqq C: \data\data\com.eg.android.AlipayGphone D: \data\data\com.tencent.xin

    以下哪个不是Android手机常见的应用程序?( ) A: \data\data\com.tencent.mm B: \data\data\com.tencent.mobileqq C: \data\data\com.eg.android.AlipayGphone D: \data\data\com.tencent.xin

  • 2022-10-30 问题

    2020/03/10-2020/03/01两个日期相减,得到的结果是

    2020/03/10-2020/03/01两个日期相减,得到的结果是

  • 2022-06-19 问题

    已知有n个数据进行排序,下面能实现排序的是 A: data=[34,5,-6,12,87,29]data.sort() B: data=[34,5,-6,12,87,29]n=len(data)od=[]whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1 C: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1print(data) D: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[i]>data[j]:t=data[i]data[i]=data[j]data[j]=tj+=1i+=1

    已知有n个数据进行排序,下面能实现排序的是 A: data=[34,5,-6,12,87,29]data.sort() B: data=[34,5,-6,12,87,29]n=len(data)od=[]whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1 C: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[j]>data[j+1]:t=data[j]data[j]=data[j+1]data[j+1]=tj+=1i+=1print(data) D: data=[34,5,-6,12,87,29]n=len(data)i=0j=0whileiwhilejifdata[i]>data[j]:t=data[i]data[i]=data[j]data[j]=tj+=1i+=1

  • 2022-06-01 问题

    表达式{^2017/03/29}-{^2017/03/20}的运算结果类型为

    表达式{^2017/03/29}-{^2017/03/20}的运算结果类型为

  • 2022-06-08 问题

    阅读下面程序:n_info = {'01': 'Python', '02': 'Java', '03': 'PHP'}n_info.update({'03': 'C++'})int(lan_info)程序,输出结果是( )。 A: {'01': 'Python', '02': 'Java', '03': 'PHP'} B: {'01': 'Python', '02': 'Java', '03': 'C++'} C: {'03': 'C++','01': 'Python', '02': 'Java'} D: {'01': 'Python', '02': 'Java'}

    阅读下面程序:n_info = {'01': 'Python', '02': 'Java', '03': 'PHP'}n_info.update({'03': 'C++'})int(lan_info)程序,输出结果是( )。 A: {'01': 'Python', '02': 'Java', '03': 'PHP'} B: {'01': 'Python', '02': 'Java', '03': 'C++'} C: {'03': 'C++','01': 'Python', '02': 'Java'} D: {'01': 'Python', '02': 'Java'}

  • 2021-04-14 问题

    有如下程序 #include intchange(int*data) { *data=*data%2; return(*data)+1; } main() { intdata=12; change(&data); printf("%d,",data); data=change(&data); printf("%d,",data); } 程序运行后的输出结果是()

    有如下程序 #include intchange(int*data) { *data=*data%2; return(*data)+1; } main() { intdata=12; change(&data); printf("%d,",data); data=change(&data); printf("%d,",data); } 程序运行后的输出结果是()

  • 2022-06-03 问题

    The data collected by the statistical survey can be original data or secondary data. The relationship between the original data and secondary data is ( ) A: The original data comes from the grass-roots units, and the secondary data comes from the superior units B: Secondary data is processed from original data C: There is no necessary connection between the original data and the secondary data D: There is no difference between primary data and secondary data

    The data collected by the statistical survey can be original data or secondary data. The relationship between the original data and secondary data is ( ) A: The original data comes from the grass-roots units, and the secondary data comes from the superior units B: Secondary data is processed from original data C: There is no necessary connection between the original data and the secondary data D: There is no difference between primary data and secondary data

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