对于数组int[][]t={{1,2,3},{4,5,6}}来说,t.length和t[0].length分别为()。 A: 12 B: 22 C: 23 D: 32
对于数组int[][]t={{1,2,3},{4,5,6}}来说,t.length和t[0].length分别为()。 A: 12 B: 22 C: 23 D: 32
假设 int[] t = {1,2,3,4}, t.length是( )?
假设 int[] t = {1,2,3,4}, t.length是( )?
假设int[]t={1,2,3,4}。t.length的值为__________? A: 0 B: 3 C: 4 D: 5
假设int[]t={1,2,3,4}。t.length的值为__________? A: 0 B: 3 C: 4 D: 5
In a copy, don’t say it’s “27 meters long”, say it’s “27 meters in length”. ( )
In a copy, don’t say it’s “27 meters long”, say it’s “27 meters in length”. ( )
182. The length of a wave is the length ______.
182. The length of a wave is the length ______.
What is the ratio of the length of the mining zone to the length of the bench?( ) A: Full length or part of it B: Full length C: Part of it D: None
What is the ratio of the length of the mining zone to the length of the bench?( ) A: Full length or part of it B: Full length C: Part of it D: None
下列代码的执行结果是: int length = "Hello".length(); System.out.println(length);
下列代码的执行结果是: int length = "Hello".length(); System.out.println(length);
下列算法实现求采用顺序结构存储的串s和串t的一个最长公共子串。 void maxcomstr(orderstring *s,*t; int index, length) {int i,j,k,length1,con; index=0;length=0;i=1; while (i
下列算法实现求采用顺序结构存储的串s和串t的一个最长公共子串。 void maxcomstr(orderstring *s,*t; int index, length) {int i,j,k,length1,con; index=0;length=0;i=1; while (i
length A: length B: launch C: lend
length A: length B: launch C: lend
已知int[][] a= {{1,2},{3,4,5,6},{7,8,9}},a.length()=_________,a[0].length()=__________, a[1].length()=__________,a[2].length()=__________,a[3].length()=__________。
已知int[][] a= {{1,2},{3,4,5,6},{7,8,9}},a.length()=_________,a[0].length()=__________, a[1].length()=__________,a[2].length()=__________,a[3].length()=__________。