字母表是 {0, 1},包含01子串的所有串为()。 A: (0|1)*(01)+ B: (0|1)*01 C: (0*010*10*)* D: (0|1)*01(0|1)*
字母表是 {0, 1},包含01子串的所有串为()。 A: (0|1)*(01)+ B: (0|1)*01 C: (0*010*10*)* D: (0|1)*01(0|1)*
If a=[1 4;5 6], c=a<5. Then c=? A: 0 1 1 0 B: 0 01 1 C: 1 10 0 D: 1 01 0
If a=[1 4;5 6], c=a<5. Then c=? A: 0 1 1 0 B: 0 01 1 C: 1 10 0 D: 1 01 0
【单选题】当表面活性剂加入溶剂后,所产生的结果是: A. dγ/da<0,正吸附; B. dγ/da<0,负吸附; C. dγ/da>0,正吸附; D. dγ/da>0,负吸附
【单选题】当表面活性剂加入溶剂后,所产生的结果是: A. dγ/da<0,正吸附; B. dγ/da<0,负吸附; C. dγ/da>0,正吸附; D. dγ/da>0,负吸附
关于变化方向的判据,以下错误的是 A: △S孤立>=0, (dA)T,V,W’>=0, (dG)T,V,W’<=0 B: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’>=0 C: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0 D: △S孤立<=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0
关于变化方向的判据,以下错误的是 A: △S孤立>=0, (dA)T,V,W’>=0, (dG)T,V,W’<=0 B: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’>=0 C: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0 D: △S孤立<=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0
【单选题】一个(3,2,1)卷积码的编码器,【图片】【图片】【图片】【图片】【图片】【图片】假设输入X=(1 1 0 1 1 0) ,求编码器编码输出 A. ( 1 10 , 0 00 , 0 01 , 111 , 0 00 , … ) B. ( 1 1 1 , 1 00 , 0 01 , 111 , 0 00 , … ) C. ( 1 1 0 , 1 00 , 1 01 , 111 , 0 00 , … ) D. ( 1 1 1 , 1 00 , 0 01 , 11 0 , 0 00 , … )
【单选题】一个(3,2,1)卷积码的编码器,【图片】【图片】【图片】【图片】【图片】【图片】假设输入X=(1 1 0 1 1 0) ,求编码器编码输出 A. ( 1 10 , 0 00 , 0 01 , 111 , 0 00 , … ) B. ( 1 1 1 , 1 00 , 0 01 , 111 , 0 00 , … ) C. ( 1 1 0 , 1 00 , 1 01 , 111 , 0 00 , … ) D. ( 1 1 1 , 1 00 , 0 01 , 11 0 , 0 00 , … )
关于变化方向的判据,以下错误的是 A: △S孤立>=0, (dA)T,V,W’>=0, (dG)T,V,W’<=0 B: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’>=0 C: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0 D: △S孤立<=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0
关于变化方向的判据,以下错误的是 A: △S孤立>=0, (dA)T,V,W’>=0, (dG)T,V,W’<=0 B: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’>=0 C: △S孤立>=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0 D: △S孤立<=0, (dA)T,V,W’<=0, (dG)T,V,W’<=0
下列码字中哪个不是唯一可译码 A: {00 01 10 11} B: {0 01 011 0111} C: {0 10 110 1110} D: {0 10 1101 1001}
下列码字中哪个不是唯一可译码 A: {00 01 10 11} B: {0 01 011 0111} C: {0 10 110 1110} D: {0 10 1101 1001}
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将下图二进制译码器的真值表补充完整,已知输出为高电平有效,A1A0=00时,Y0有效,A1A0=01时,Y1 有效,A1A0=10时,Y2 有效,A1A0=11时,Y3有效。A1A0Y0 Y1 Y2 Y30 00 11 0 1 1 A: A1A0Y0 Y1 Y2 Y30 00 1 1 10 11 0 1 11 0 1 1 0 11 11 1 1 0 B: A1A0Y0 Y1 Y2 Y30 01 0 0 00 10 1 0 01 0 0 0 1 01 10 0 0 1
将下图二进制译码器的真值表补充完整,已知输出为高电平有效,A1A0=00时,Y0有效,A1A0=01时,Y1 有效,A1A0=10时,Y2 有效,A1A0=11时,Y3有效。A1A0Y0 Y1 Y2 Y30 00 11 0 1 1 A: A1A0Y0 Y1 Y2 Y30 00 1 1 10 11 0 1 11 0 1 1 0 11 11 1 1 0 B: A1A0Y0 Y1 Y2 Y30 01 0 0 00 10 1 0 01 0 0 0 1 01 10 0 0 1
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