下面程序的运行结果是（）。#includeintmain(){inta,s,n,count;a=2;s=0;n=1;count=1;while(count<=7){n=n*a;s=s+n;++count;}printf(“%d”,s);return0;}

下面程序的输出结果是（ ）。class Student: count = 0 def __init__(self, name): self.name = name Student.count += 1s1 = Student("Alex")s2 = Student("Jack")print(s1.count)

使用while 语句实现打印出1至10.count = 1while ( ) print (count) count = count + 1 A: count B: True C: count D: count

count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")

阅读以下程序public class Count{static int count;int number;public Count(){count = count + 1;number = count;}}class Test{public static void Main(){Count a = new Count();Count b = new Count();Count c = new Count();}}程序运行后，对象a的count值是（） A: 0 B: 1 C: 2 D: 3

下面的代码段执行之后count的值是什么( ) int count = 1; for(int i = 1; i <= 5; i++) { count+= i; } System.out.println(count); int count = 1; for(int i = 1; i <= 5; i++) { count+= i; } System.out.println(count);

下面的代码段执行之后count的值是什么( ) int count = 1; for (int i = 1; i <= 5; i++) { count += i; } System.out.println(count);

The output of the following code is ____.<br/>count = 1; /* initialize count */ while (count &lt;= 10) { printf("%d ",count); count++; /* increment count */ } A: 1 1 1 1 1 1 1 1 … B: 1 2 3 4 5 6 7 8 9 C: 1 2 3 4 5 6 7 8 9 10 D: 1 2 3 4 5 6 7 8 9 10 11

将变量$count增1，下面哪种方式是正确的？（ ） A: $count =+1; B: ++ count; C: count++; D: $count++;

下列SQL语句中，正确的是（ ）。 A: SELECT S B: , SNAME FROM SC GROUP BY S C: SELECT S D: FROM SC GROUP BY S E: HAVING COUNT(*)>3 F: SELECT S G: ,Cname FROM SC GROUP BY S H: WHERE COUNT(*)>3 I: SELECT S J: FROM SC WHERE COUNT(*)>3 GROUP BY S