合法的数组定义是（ ）。 A: int a[]="Language"; B: int a[5]={0,1,2,3,4,5}; C: char a="C Program"; D: char a[]="C Program Language.";

以下合法的数组定义是( )。 A: int a[]="Language"; B: char a[]="C Program Language."; C: char a="C Program"; D: int a[5]={0,1,2,3,4,5};

There are ( ) basic paths for the following program.int FUN(int count, int flag){ int temp=0; while(count>0){ if(0==flag){ temp=count+100; } else{ if(1==flag) temp=temp+10; else temp=temp+20; } count--; } return temp;} A: 2 B: 3 C: 4 D: 4

预测下面程序的输出：// PROGRAM 1#include <stdio.h>int main(void){ int arr[] = {10, 20}; int *p = arr; ++*p; printf("arr[0] = %d, arr[1] = %d, *p = %d", arr[0], arr[1], *p); return 0;}// PROGRAM 2#include <stdio.h>int main(void){ int arr[] = {10, 20}; int *p = arr; *p++; printf("arr[0] = %d, arr[1] = %d, *p = %d", arr[0], arr[1], *p); return 0;}// PROGRAM 3#include <stdio.h>int main(void){ int arr[] = {10, 20}; int *p = arr; *++p; printf("arr[0] = %d, arr[1] = %d, *p = %d", arr[0], arr[1], *p); return 0;}

中国大学MOOC: The output of the following program is main(){ int n=4; while (n--) printf(%d,--n)；}

中国大学MOOC:"下面程序的功能是将字符数组中存放的字符串以多种书写形式输出，如“Program”，“PROGRAM”，以及逆序输出的字符串“margorp”等，程序的运行结果为：ProgramPROGRAMmargorp按要求在空白处填写适当的表达式或语句，使程序完整并符合题目要求。#include #include int main(void) { int i = 0; char b[] = "program"; char *a = "PROGRAM"; printf("_____ ", *a, b + 1); /* 输出Program */ while (_________________) /* 输出PROGRAM */ { ___________; i++; } printf(" "); while (_____) /* 输出margorp */ { putchar (___________); } __________; return 0; }";

合法的数组定义是（ ）。 A: int a[]="Language"; B: int a[5]={0,1,2,3,4,5}; C: char a="C Program"; D: char a[]="C Program Language.";

Analyze the running process of the following program and write the running results#include int main(){ int a=3,b=5,t=2; if(a>b) {t=a;a=b;b=t;} printf("%d",a);}______

Analyze the running process of the following program and write the running results.#includeint main(){ int a=6; printf("%d\n",a%=a+=a-=a*a); return 0;}______

Analyze the running process of the following program and write the running results#includeint main(){ int a=3; printf("%d\n",a-=a*=a+=a%a); return 0;}______