下列结果表达式,正确的是( ) A: N=(3.0425±0.06)×10-11N∙m-2 B: N=(3.0425±0.058)×10-11N∙m-2 C: N=(3.04±0.06)×10-11N∙m-2 D: N=(3.04×10-11±0.58×10-10)N∙m-2
下列结果表达式,正确的是( ) A: N=(3.0425±0.06)×10-11N∙m-2 B: N=(3.0425±0.058)×10-11N∙m-2 C: N=(3.04±0.06)×10-11N∙m-2 D: N=(3.04×10-11±0.58×10-10)N∙m-2
脑神经共有()对。 A: 10\n B: 11\n C: 12\n D: 13
脑神经共有()对。 A: 10\n B: 11\n C: 12\n D: 13
严复翻译了()部西方名著。 A: 8;\n B: 10;\n C: 11;\n D: 12
严复翻译了()部西方名著。 A: 8;\n B: 10;\n C: 11;\n D: 12
9.- سائەتكە قاراڭ،نەچچە بولدى؟正确回答是 ( ) A: سائەت 11 غا 10مىنۇت ئۆتتى. B: سائەت 11 دىن 10مىنۇت قالدى. C: سائەت 11 10مىنۇت ئۆتتى. D: سائەت 11 دىن 10مىنۇت ئۆتتى.
9.- سائەتكە قاراڭ،نەچچە بولدى؟正确回答是 ( ) A: سائەت 11 غا 10مىنۇت ئۆتتى. B: سائەت 11 دىن 10مىنۇت قالدى. C: سائەت 11 10مىنۇت ئۆتتى. D: سائەت 11 دىن 10مىنۇت ئۆتتى.
请问如下算法运行完之后n,n1,n2分别是多少? var n1=10, n2=20; n = n1++; n = ++n1; n = n2--; n = --n2; A: n=18, n1=12, n2=18 B: n=11, n1=11, n2=19 C: n=12, n1=12, n2=18 D: n=19, n1=11, n2=19
请问如下算法运行完之后n,n1,n2分别是多少? var n1=10, n2=20; n = n1++; n = ++n1; n = n2--; n = --n2; A: n=18, n1=12, n2=18 B: n=11, n1=11, n2=19 C: n=12, n1=12, n2=18 D: n=19, n1=11, n2=19
n=11的回归分析中,总平方和为30,残差平方和为10,则回归的方差为( )。 A: 30 B: 20 C: 10 D: 11
n=11的回归分析中,总平方和为30,残差平方和为10,则回归的方差为( )。 A: 30 B: 20 C: 10 D: 11
执行以下程序输出结果是_______.#include <;stdio.h>;void main( ){ int n=9; if(n++ <; 10) printf("%d\n", n); else printf("%d\n", n--);} A: 11 B: 10 C: 9 D: 8
执行以下程序输出结果是_______.#include <;stdio.h>;void main( ){ int n=9; if(n++ <; 10) printf("%d\n", n); else printf("%d\n", n--);} A: 11 B: 10 C: 9 D: 8
循环语句for($n = 10;$n>=0; $n--)的循环次数为( )。 A: 4 B: 5 C: 11 D: 10
循环语句for($n = 10;$n>=0; $n--)的循环次数为( )。 A: 4 B: 5 C: 11 D: 10
有以下程序段:#include int main(){int x[ ] = {10, 20, 30}; int *px = x;printf("%d, ", ++*px); printf("%d, ", *px); px = x;printf("%d, ", (*px)++); printf("%d, ", *px); px = x;printf("%d, ", *px++); printf("%d, ", *px); px = x;printf("%d, ", *++px); printf("%d\n", *px);return 0;}程序运行后的输出结果是( ) A: 20, 10, 11, 10, 11, 10, 11, 10 B: 11, 11, 11, 12, 12, 20, 20, 20 C: 20, 10, 11, 20, 11, 12, 20, 20 D: 11, 11, 11, 12, 12, 13, 20, 20
有以下程序段:#include int main(){int x[ ] = {10, 20, 30}; int *px = x;printf("%d, ", ++*px); printf("%d, ", *px); px = x;printf("%d, ", (*px)++); printf("%d, ", *px); px = x;printf("%d, ", *px++); printf("%d, ", *px); px = x;printf("%d, ", *++px); printf("%d\n", *px);return 0;}程序运行后的输出结果是( ) A: 20, 10, 11, 10, 11, 10, 11, 10 B: 11, 11, 11, 12, 12, 20, 20, 20 C: 20, 10, 11, 20, 11, 12, 20, 20 D: 11, 11, 11, 12, 12, 13, 20, 20
有以下程序段:#include stdio.hint main(){int x[ ] = {10, 20, 30}; int *px = x;printf(%d, , ++*px); printf(%d, , *px); px = x;printf(%d, , (*px)++); printf(%d, , *px); px = x;printf(%d, , *px++); printf(%d, , *px); px = x;printf(%d, , *++px); printf(%d\n, *px);return 0;}程序运行后的输出结果是( )。 A: 11, 11, 11, 12, 12, 20, 20, 20 B: 20, 10, 11, 10, 11, 10, 11, 10 C: 11, 11, 11, 12, 12, 13, 20, 20 D: 20, 10, 11, 20, 11, 12, 20, 20
有以下程序段:#include stdio.hint main(){int x[ ] = {10, 20, 30}; int *px = x;printf(%d, , ++*px); printf(%d, , *px); px = x;printf(%d, , (*px)++); printf(%d, , *px); px = x;printf(%d, , *px++); printf(%d, , *px); px = x;printf(%d, , *++px); printf(%d\n, *px);return 0;}程序运行后的输出结果是( )。 A: 11, 11, 11, 12, 12, 20, 20, 20 B: 20, 10, 11, 10, 11, 10, 11, 10 C: 11, 11, 11, 12, 12, 13, 20, 20 D: 20, 10, 11, 20, 11, 12, 20, 20