已知某正弦量的有效值相量为30∠-30°V,电路的频率为f=50Hz,则该正弦量的瞬时值表达式为() 未知类型:{'options': ['30cos([img=62x17]17e43c56178eac7.jpg[/img])', ' 30[img=21x20]17e43630963ca84.jpg[/img]cos([img=62x17]17e43c56178eac7.jpg[/img])', ' 30[img=21x20]17e43630963ca84.jpg[/img]cos([img=71x17]17e43c561fd2fbf.jpg[/img])', ' 30[img=21x19]17e435c1ed35b3d.jpg[/img]cos([img=71x17]17e43c561fd2fbf.jpg[/img])'], 'type': 102}
已知某正弦量的有效值相量为30∠-30°V,电路的频率为f=50Hz,则该正弦量的瞬时值表达式为() 未知类型:{'options': ['30cos([img=62x17]17e43c56178eac7.jpg[/img])', ' 30[img=21x20]17e43630963ca84.jpg[/img]cos([img=62x17]17e43c56178eac7.jpg[/img])', ' 30[img=21x20]17e43630963ca84.jpg[/img]cos([img=71x17]17e43c561fd2fbf.jpg[/img])', ' 30[img=21x19]17e435c1ed35b3d.jpg[/img]cos([img=71x17]17e43c561fd2fbf.jpg[/img])'], 'type': 102}
已知电流i1=10sin(200πt+60°)A,i2=30cos(200πt+30°)A,则i1与i2相位关系为() A: 超前30° B: 滞后30° C: 滞后60° D: 超前60°
已知电流i1=10sin(200πt+60°)A,i2=30cos(200πt+30°)A,则i1与i2相位关系为() A: 超前30° B: 滞后30° C: 滞后60° D: 超前60°
若a<60°,且sin(60°-a)=1215,则cos(30°+a)=______.
若a<60°,且sin(60°-a)=1215,则cos(30°+a)=______.
sin 54°cos 24°-sin36°sin 24°=sin 30°.
sin 54°cos 24°-sin36°sin 24°=sin 30°.
下列计算正确的是() A: log2cos7π4=-12 B: 若f(cos x)=cos 2x,则f(sin 30°)=12 C: 若sin(π+α)=-12,则sin(4π-α)=-12 D: 设tan(π+α)=2,则sin(α-π)+cos(π-α)sin(π+α)-cos(π-α)=1
下列计算正确的是() A: log2cos7π4=-12 B: 若f(cos x)=cos 2x,则f(sin 30°)=12 C: 若sin(π+α)=-12,则sin(4π-α)=-12 D: 设tan(π+α)=2,则sin(α-π)+cos(π-α)sin(π+α)-cos(π-α)=1
【单选题】sin ( α+β ) = A. sinαcosβ-cosαsinβ B. cosαsin β-sin αcos β C. sinαcosβ+cosαsinβ D. cos αcos β-sin α sin β
【单选题】sin ( α+β ) = A. sinαcosβ-cosαsinβ B. cosαsin β-sin αcos β C. sinαcosβ+cosαsinβ D. cos αcos β-sin α sin β
【单选题】设y=sin(cos(x)),求 结果为:(本题10.0分) A. cos(cos(x))*cos(x)+ sin(cos(x))*sin(x)^2 B. - cos(cos(x))*cos(x) - sin(cos(x))*sin(x)^2 C. - cos(cos(x))*cos(x)^2 - sin(cos(x))*sin(x)^2 D. - cos(cos(x))*cos(x) ^2- sin(cos(x))*sin(x)
【单选题】设y=sin(cos(x)),求 结果为:(本题10.0分) A. cos(cos(x))*cos(x)+ sin(cos(x))*sin(x)^2 B. - cos(cos(x))*cos(x) - sin(cos(x))*sin(x)^2 C. - cos(cos(x))*cos(x)^2 - sin(cos(x))*sin(x)^2 D. - cos(cos(x))*cos(x) ^2- sin(cos(x))*sin(x)
cos(x)*cos(x/2)*cos(x/4)*cos(x/8).cos(x/(2^(n-1))
cos(x)*cos(x/2)*cos(x/4)*cos(x/8).cos(x/(2^(n-1))
\(设f(x,y,z)=\frac{x\cos y+y\cos z+z\cos x}{1+\cos x+\cos y+\cos z},则df|_{(0,0,0)}=(\,)\)
\(设f(x,y,z)=\frac{x\cos y+y\cos z+z\cos x}{1+\cos x+\cos y+\cos z},则df|_{(0,0,0)}=(\,)\)
sin(α-β)cosβ+cos(α-β)sinβ=( ) A: sin(α-2β) B: cos(α-2β) C: sinα D: cosα
sin(α-β)cosβ+cos(α-β)sinβ=( ) A: sin(α-2β) B: cos(α-2β) C: sinα D: cosα