int x,y; x=9%5; y=9/5 则x=,y=。
int x,y; x=9%5; y=9/5 则x=,y=。
表示x是5的倍数或是9的倍数的逻辑表达式为 ____。 A: x \ 5 = 0 Or x \ 9 = 0 B: x \ 5 = 0 And x \ 9 = 0 C: x Mod 5 = 0 Or x Mod 9 = 0 D: x Mod 5 = 0 And x Mod 9 = 0
表示x是5的倍数或是9的倍数的逻辑表达式为 ____。 A: x \ 5 = 0 Or x \ 9 = 0 B: x \ 5 = 0 And x \ 9 = 0 C: x Mod 5 = 0 Or x Mod 9 = 0 D: x Mod 5 = 0 And x Mod 9 = 0
执行以下代码之后,x、y的值分别为多少?varx,y=9;x=y++; A: x为9,y为9 B: x为10,y为10 C: x为10,y为9 D: x为9,y为10
执行以下代码之后,x、y的值分别为多少?varx,y=9;x=y++; A: x为9,y为9 B: x为10,y为10 C: x为10,y为9 D: x为9,y为10
已知 x = (3), 那么表达式 x * 3 的值为( )。 A: 9 B: (9,) C: (0,9) D: (9,None)
已知 x = (3), 那么表达式 x * 3 的值为( )。 A: 9 B: (9,) C: (0,9) D: (9,None)
以4,9,1为为插值节点,求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)
以4,9,1为为插值节点,求\(\sqrt x \)的lagrange的插值多项式 A: \( {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) B: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) + {1 \over {24}}(x - 4)(x - 9)\) C: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x +1) + {1 \over {24}}(x - 4)(x - 9)\) D: \( - {2 \over {15}}(x - 9)(x - 1) + {3 \over {40}}(x - 4)(x - 1) - {1 \over {24}}(x - 4)(x - 9)\)
下面代码的输出结果是()。def f(): x=198 print(x) x=9 f() print(x) A: 198 198 B: 198 9 C: 9 198 D: 出错
下面代码的输出结果是()。def f(): x=198 print(x) x=9 f() print(x) A: 198 198 B: 198 9 C: 9 198 D: 出错
设X ~ N(2, 9)则Y = (X – 2 )/9 ~ N(0, 1).
设X ~ N(2, 9)则Y = (X – 2 )/9 ~ N(0, 1).
X 服从参数为1/9的指数分布,则P{3<X<9}=( )
X 服从参数为1/9的指数分布,则P{3<X<9}=( )
下面代码的输出结果是()。def f(): global x x=198 print(x) x=9 f() print(x) A: 198 198 B: 198 9 C: 9 198 D: 出错
下面代码的输出结果是()。def f(): global x x=198 print(x) x=9 f() print(x) A: 198 198 B: 198 9 C: 9 198 D: 出错
缓和曲线采用切线支距法计算坐标的公式为() A: x=ι-ι4/(40R2I02)+ι9/(3456R4I04)… B: x=ι-ι5/(40R2I02)+ι9/(3456R4I04)… C: x=ι-ι3/(40R2I02)+ι9/(3456R4I04)… D: x=ι-ι2/(40R2I02)+ι9/(3456R4I04)…
缓和曲线采用切线支距法计算坐标的公式为() A: x=ι-ι4/(40R2I02)+ι9/(3456R4I04)… B: x=ι-ι5/(40R2I02)+ι9/(3456R4I04)… C: x=ι-ι3/(40R2I02)+ι9/(3456R4I04)… D: x=ι-ι2/(40R2I02)+ι9/(3456R4I04)…