你手机四年的 A: xjd B: dd C: 大家的 D: xx

用消元法解下列方程组．[tex=11.643x5.214]fnpmC2J6JmQBLyo5NmGAz0t+pDmn7LB0YTA1A4SoVysMskcybcmheUApjO/1go1//fm+FJ52Uwz5G2p/JyimeAYBk0QbItr4xOY9sC52Xuo4QmbImta+zz+HTpP0OgaC+stIrcILOvkH/buGni8pNQR18dYVxzw5j5mwabV92BQiNPH/xJD/q8fwCjysJUC5ZPsOVfduzeveeSxdx5uysF4iFIlWsGGRpIV/mUON4PM=[/tex]．

已知线路方向上两相邻缓和曲线,交点分别为JD1和JD2,JD1和JD2之间的距离为600m,JD1到JD2的坐标方位角为106°48′25″,JD1处的切线长T1为80m,JD1的坐标XJD1=500.000m,JD2处的切线长T2为120m,则JD1处HZ点坐标X=___m

如图,初测导线点C1之坐标XC1=1265.50m,YC1=1980.44m,C1C2之坐标方位角为120°13′36″,由设计图上量得设计中线的交点JD1之坐标为XJD1=1180.45m,YJD1=1860.24m,交点JD2之坐标为XJD2=1206.70m,YJD2=2150.09m,试计算用拨角放线法测设出JD1、JD2所需数据,并依据数据简述其测设方法。

如图,初测导线点C1之坐标XC1=1265.50m,YC1=1980.44m,C1C2之坐标方位角为120°13′36″,由设计图上量得设计中线的交点JD1之坐标为XJD1=1180.45m,YJD1=1860.24m,交点JD2之坐标为XJD2=1206.70m,YJD2=2150.09m,试计算用拨角放线法测设出JD1、JD2所需数据,并依据数据简述其测设方法。761c2dc4444e6a81115fb7a17391176d.png

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4