【单选题】下列选项中能正确表达 0 成立的逻辑表达式的是 A. x>0 or x<5 B. x>0 and x<1000 C. x>0 & x<1000 D. x>0,x<1000
【单选题】下列选项中能正确表达 0 成立的逻辑表达式的是 A. x>0 or x<5 B. x>0 and x<1000 C. x>0 & x<1000 D. x>0,x<1000
蓄电池的循环寿命与放电深度成反比.(622)()
蓄电池的循环寿命与放电深度成反比.(622)()
下列不是物流模数规格1200 X 1000毫米集装的基础模数尺寸。 A: 1000 X 600 B: 1000 X 400 C: 500 X 400 D: 600 X 400
下列不是物流模数规格1200 X 1000毫米集装的基础模数尺寸。 A: 1000 X 600 B: 1000 X 400 C: 500 X 400 D: 600 X 400
x=10y=3print(x%y,x**y)上面代码的输出结果是( )。 A: 3 30 B: 1 1000 C: 1 30 D: 3 1000
x=10y=3print(x%y,x**y)上面代码的输出结果是( )。 A: 3 30 B: 1 1000 C: 1 30 D: 3 1000
下面代码的输出结果是( )X=10Y=3print(X % Y, X * Y) A: 3 1000 B: 1 30 C: 3 30 D: 1 1000
下面代码的输出结果是( )X=10Y=3print(X % Y, X * Y) A: 3 1000 B: 1 30 C: 3 30 D: 1 1000
设[X]补码=1000 0011,则X的真值为( )
设[X]补码=1000 0011,则X的真值为( )
下图昆虫为()昆虫。[img=1000x622]17e439b1f662044.png[/img] A: 直翅目 B: 半翅目 C: 鞘翅目 D: 缨翅目
下图昆虫为()昆虫。[img=1000x622]17e439b1f662044.png[/img] A: 直翅目 B: 半翅目 C: 鞘翅目 D: 缨翅目
智慧职教: 一个2.0m机柜可安装( )个OptiX155/622子架
智慧职教: 一个2.0m机柜可安装( )个OptiX155/622子架
You are offered an investment opportunity. Its outcomes and probabilities are presented in the following table. X P(X) –$1000 .40 $0 .20 +$1000 .40 The mean of this distribution is _____________.
You are offered an investment opportunity. Its outcomes and probabilities are presented in the following table. X P(X) –$1000 .40 $0 .20 +$1000 .40 The mean of this distribution is _____________.
题目:给一个不多于5位的正整数,要求:一、求它是几位数,二、逆序打印出各位数字。x = int(input("input a number:"))a = x // 10000________________c = x % 1000 // 100d = x % 100 // 10e = x % 10if a != 0: print ("there are 5 ",e,d,c,b,a)elif b != 0: print ("there are 4 ",d,c,b,a)elif c != 0: print ("there are 3 ",e,d,c)elif d != 0: print ("there are 2 ",e,d)else: print ("there are 1",e) A: b = x // 10000 // 1000 B: b = x % 10000 // 1000 C: b = x // 10000 % 1000 D: b = x % 10000 % 1000
题目:给一个不多于5位的正整数,要求:一、求它是几位数,二、逆序打印出各位数字。x = int(input("input a number:"))a = x // 10000________________c = x % 1000 // 100d = x % 100 // 10e = x % 10if a != 0: print ("there are 5 ",e,d,c,b,a)elif b != 0: print ("there are 4 ",d,c,b,a)elif c != 0: print ("there are 3 ",e,d,c)elif d != 0: print ("there are 2 ",e,d)else: print ("there are 1",e) A: b = x // 10000 // 1000 B: b = x % 10000 // 1000 C: b = x // 10000 % 1000 D: b = x % 10000 % 1000