• 2022-05-29 问题

    All Chinese people know Kung Fu.

    All Chinese people know Kung Fu.

  • 2022-06-07 问题

    GSM900频点计算公式为? A: FU=890+N*0.2MHzFD= FU +95MHz B: FU=1710+N*0.2MHzFD= FU +95MHz C: FU=1710+N*0.2MHzFD= FU +45MHz D: FU=890+N*0.2MHzFD= FU +45MHz

    GSM900频点计算公式为? A: FU=890+N*0.2MHzFD= FU +95MHz B: FU=1710+N*0.2MHzFD= FU +95MHz C: FU=1710+N*0.2MHzFD= FU +45MHz D: FU=890+N*0.2MHzFD= FU +45MHz

  • 2022-05-29 问题

    The northern style is closely related to the martial art from Kung Fu.

    The northern style is closely related to the martial art from Kung Fu.

  • 2022-05-30 问题

    Some Westerns think Chinese people are all good at Kong Fu. They are ________________.

    Some Westerns think Chinese people are all good at Kong Fu. They are ________________.

  • 2022-06-11 问题

    下列不是前后轮同时抱死的条件是()。 A: Fu+F=φG B: Fu=φFz C: Fu=φFz D: =Fu/Fu

    下列不是前后轮同时抱死的条件是()。 A: Fu+F=φG B: Fu=φFz C: Fu=φFz D: =Fu/Fu

  • 2022-06-11 问题

    8.8级高螺栓是指()。 A: 抗拉强度fu≥800N/mm2 B: fu≥800N/mm2,fy/fu=0.8 C: fu<800N/mm2fy/fu=0.8 D: 含碳量不小于万分之8.8

    8.8级高螺栓是指()。 A: 抗拉强度fu≥800N/mm2 B: fu≥800N/mm2,fy/fu=0.8 C: fu<800N/mm2fy/fu=0.8 D: 含碳量不小于万分之8.8

  • 2022-06-19 问题

    8.8级高强度螺栓数字的含义指( )。 A: fu≥8.8KN/mm2 B: fu≥800N/mm2, fy/fu=0.8 C: fu<;800N/mm2, fy/fu=0.8 D: 含碳量不小于万分之8.8

    8.8级高强度螺栓数字的含义指( )。 A: fu≥8.8KN/mm2 B: fu≥800N/mm2, fy/fu=0.8 C: fu<;800N/mm2, fy/fu=0.8 D: 含碳量不小于万分之8.8

  • 2022-06-05 问题

    材料的价值即性价比为( )。 A: Fu/C B: C/Fu C: Fu/(C+Fu ) D: C/(C+Fu )

    材料的价值即性价比为( )。 A: Fu/C B: C/Fu C: Fu/(C+Fu ) D: C/(C+Fu )

  • 2022-05-27 问题

    Sorrow after Departure, the longest poem in ancient China, reflects the life story and the patriotism of Du Fu.

    Sorrow after Departure, the longest poem in ancient China, reflects the life story and the patriotism of Du Fu.

  • 2022-10-29 问题

    DCS1800的频点计算公式是? A: Fu=1710+(n-311)*0.2MHzFd=Fu+95MHz B: Fu=1710+(n-511)*0.2MHzFd=Fu+95MHz C: Fu=1710+(n-511)*0.2MHzFd=Fu+45MHz D: Fu=1710+n*0.2MHzFd=Fu+95MHz

    DCS1800的频点计算公式是? A: Fu=1710+(n-311)*0.2MHzFd=Fu+95MHz B: Fu=1710+(n-511)*0.2MHzFd=Fu+95MHz C: Fu=1710+(n-511)*0.2MHzFd=Fu+45MHz D: Fu=1710+n*0.2MHzFd=Fu+95MHz

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