已知英文字母m的ASCII码值为109,那么英文字母p的() A: 111 B: 112 C: 113 D: 114
已知英文字母m的ASCII码值为109,那么英文字母p的() A: 111 B: 112 C: 113 D: 114
已知英文字母m的ASCII码值为109,那么英文字母p的() A: 111 B: 112 C: 113 D: 114
已知英文字母m的ASCII码值为109,那么英文字母p的() A: 111 B: 112 C: 113 D: 114
地铁4号线站台边缘设置有屏蔽门,屏蔽门的总长度为()m。 A: 112 B: 113 C: 114 D: 120
地铁4号线站台边缘设置有屏蔽门,屏蔽门的总长度为()m。 A: 112 B: 113 C: 114 D: 120
112
112
下面代码的执行结果是: ls = [“2020”, “2020”, “Python”] ls.append(2020) ls.append([2020, “2020”]) print(ls): [‘2020’, ‘2020’, ‘Python’, 2020, 2020, ‘2020’]|[‘2020’, ‘2020’, ‘Python’, 2020, [2020, ‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020, [‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020]
下面代码的执行结果是: ls = [“2020”, “2020”, “Python”] ls.append(2020) ls.append([2020, “2020”]) print(ls): [‘2020’, ‘2020’, ‘Python’, 2020, 2020, ‘2020’]|[‘2020’, ‘2020’, ‘Python’, 2020, [2020, ‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020, [‘2020’]]|[‘2020’, ‘2020’, ‘Python’, 2020]
time.strftime('%m', time.localtime(x))输出结果为 A: 2021 B: 2020 C: 7 D: 12
time.strftime('%m', time.localtime(x))输出结果为 A: 2021 B: 2020 C: 7 D: 12
112窟
112窟
已知英文字母m的ASCII码为109,那么字母P的ASCII码为:______ A: 111 B: 112 C: 113 D: 114
已知英文字母m的ASCII码为109,那么字母P的ASCII码为:______ A: 111 B: 112 C: 113 D: 114
下面代码的执行结果是( ) 。ls = ["2020", "20.20", "Python"] ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020, 2020, '2020'] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, ['2020']]
下面代码的执行结果是( ) 。ls = ["2020", "20.20", "Python"] ls.append(2020)ls.append([2020, "2020"])print(ls) A: ['2020', '20.20', 'Python', 2020, 2020, '2020'] B: ['2020', '20.20', 'Python', 2020, [2020, '2020']] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, ['2020']]
下面代码的执行结果是: ls = ["2020", "20.20", "Python"] ls.append(2020) ls.append([2020, "2020"]) print(ls) A: ['2020', '20.20', 'Python', 2020, ['2020']] B: ['2020', '20.20', 'Python', 2020, 2020, '2020'] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, [2020, '2020']]
下面代码的执行结果是: ls = ["2020", "20.20", "Python"] ls.append(2020) ls.append([2020, "2020"]) print(ls) A: ['2020', '20.20', 'Python', 2020, ['2020']] B: ['2020', '20.20', 'Python', 2020, 2020, '2020'] C: ['2020', '20.20', 'Python', 2020] D: ['2020', '20.20', 'Python', 2020, [2020, '2020']]