• 2022-06-04 问题

    写出下面程序的输出结果 publicclassTestjava{ publicstaticvoidmain(String[]args){ Stringstr="abbaefabbewbvwabbswgfga"; System.out.println("count="+getSubCount(str,"abb")); } publicstaticintgetSubCount(Stringstr,Stringkey){ intcount=0; intindex=0; while((index=str.indexOf(key,index))!=-1){ System.out.println("index="+index); index=index+key.length(); count++; } returncount; } }

    写出下面程序的输出结果 publicclassTestjava{ publicstaticvoidmain(String[]args){ Stringstr="abbaefabbewbvwabbswgfga"; System.out.println("count="+getSubCount(str,"abb")); } publicstaticintgetSubCount(Stringstr,Stringkey){ intcount=0; intindex=0; while((index=str.indexOf(key,index))!=-1){ System.out.println("index="+index); index=index+key.length(); count++; } returncount; } }

  • 2022-10-26 问题

    CREATE TABLE语句用于创建索引的子句是( ) 。 A: 只能用index B: 只能用key C: index或key D: keys

    CREATE TABLE语句用于创建索引的子句是( ) 。 A: 只能用index B: 只能用key C: index或key D: keys

  • 2021-04-14 问题

    Variation in length of sentences can be used to emphasize a key idea.

    Variation in length of sentences can be used to emphasize a key idea.

  • 2022-05-26 问题

    The index of coincidence: A: can tell you the likelihood that a key is the same length as the ciphertext B: can tell you the likelihood that some ciphertext has the same frequency counts as English C: can distinguish between mono and polyalphabetic substitution ciphers D: a and b only.

    The index of coincidence: A: can tell you the likelihood that a key is the same length as the ciphertext B: can tell you the likelihood that some ciphertext has the same frequency counts as English C: can distinguish between mono and polyalphabetic substitution ciphers D: a and b only.

  • 2022-06-07 问题

    创建普通索引使用()。 A: KEY B: INDEX C: UNIQUEINDEX D: PRIMARYKEY

    创建普通索引使用()。 A: KEY B: INDEX C: UNIQUEINDEX D: PRIMARYKEY

  • 2022-05-26 问题

    下面哪个属性或方法是返回字符串中字符的个数? A: length B: charAt(index) C: substr(startIndex[, length]) D: indexOf(str[,startIndex])

    下面哪个属性或方法是返回字符串中字符的个数? A: length B: charAt(index) C: substr(startIndex[, length]) D: indexOf(str[,startIndex])

  • 2022-06-15 问题

    在Create Table语句中,【 】短语能创建索引。 A: Primary Key B: Foreign Key C: References D: Unique E: Index

    在Create Table语句中,【 】短语能创建索引。 A: Primary Key B: Foreign Key C: References D: Unique E: Index

  • 2022-06-15 问题

    在Create Table语句中,()短语能定义表的关键字。 A: Constraint B: Foreign Key C: Primary Key D: Index E: Unique

    在Create Table语句中,()短语能定义表的关键字。 A: Constraint B: Foreign Key C: Primary Key D: Index E: Unique

  • 2022-06-01 问题

    下列算法实现求采用顺序结构存储的串s和串t的一个最长公共子串。void maxcomstr(orderstring *s,*t, int index, length){int i,j,k,length1,con; index=0;length=0;i=1; while (i&#91;=s.len) {j=1;while(j<=t.len){ if (s[i]==t&#91;j&#93;) { k=1;length1=1;con=1; while(con) if (1) _ { length1=length1+1;k=k+1; } else (2) __; if (length1&#93;length) { index=i; length=length1; } (3)____; } else (4) ___; } (5) __} }[/i]

    下列算法实现求采用顺序结构存储的串s和串t的一个最长公共子串。void maxcomstr(orderstring *s,*t, int index, length){int i,j,k,length1,con; index=0;length=0;i=1; while (i&#91;=s.len) {j=1;while(j<=t.len){ if (s[i]==t&#91;j&#93;) { k=1;length1=1;con=1; while(con) if (1) _ { length1=length1+1;k=k+1; } else (2) __; if (length1&#93;length) { index=i; length=length1; } (3)____; } else (4) ___; } (5) __} }[/i]

  • 2022-06-08 问题

    下面选项中,不是jQuery访问的方法的 A: each(callback) B: size() C: index() D: length()

    下面选项中,不是jQuery访问的方法的 A: each(callback) B: size() C: index() D: length()

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