• 2022-06-06 问题

    What information in the shared bicycle system is impossible for the electronic lock to report to the platform A: Geographic location B: battery power C: User Info D: Conversation message

    What information in the shared bicycle system is impossible for the electronic lock to report to the platform A: Geographic location B: battery power C: User Info D: Conversation message

  • 2021-04-14 问题

    阅读下列程序段,写出运行结果 ________ 。 struct user_info { charname[20]; int age; charphone[20]; charaddress[80]; }; typedef struct user_infoUSERINFO; inti,j,k; USERINFOtmp; USERINFOuser[5]= { {"Li",31,"62201100","Beijing"}, {"Wang",29,"12347899","Xi an"}, {"Anqi",20,"76769892","Shanghai"}, {"Zhang",46,"87432234","Tianjin"}, {"Yang",33,"87651234","Shenyang"} }; for(i=1;i<5;i++) { k=5-i; for(j=0;j<5-i;j++) if(stricmp(user[j].name,user[k].name)>0) k=j; if(k!=5-i) { tmp=user[k]; user[k]=user[5-i]; user[5-i]=tmp; } } for(i=0;i<5;i++) printf("%s",user[i].name);

    阅读下列程序段,写出运行结果 ________ 。 struct user_info { charname[20]; int age; charphone[20]; charaddress[80]; }; typedef struct user_infoUSERINFO; inti,j,k; USERINFOtmp; USERINFOuser[5]= { {"Li",31,"62201100","Beijing"}, {"Wang",29,"12347899","Xi an"}, {"Anqi",20,"76769892","Shanghai"}, {"Zhang",46,"87432234","Tianjin"}, {"Yang",33,"87651234","Shenyang"} }; for(i=1;i<5;i++) { k=5-i; for(j=0;j<5-i;j++) if(stricmp(user[j].name,user[k].name)>0) k=j; if(k!=5-i) { tmp=user[k]; user[k]=user[5-i]; user[5-i]=tmp; } } for(i=0;i<5;i++) printf("%s",user[i].name);

  • 2022-06-05 问题

    Which step is designed to prompt a user to press or say a single-digit number to perform a specific function? () A: Menu   B: Get Digit String   C: Get Call Contact Info   D: Extended Get Digit String

    Which step is designed to prompt a user to press or say a single-digit number to perform a specific function? () A: Menu   B: Get Digit String   C: Get Call Contact Info   D: Extended Get Digit String

  • 2022-06-08 问题

    在Linux中,显示info文件的前3行,可以用以下()命令。 A: head -3 info B: cat -3 info C: tail -3 info D: more -3 info

    在Linux中,显示info文件的前3行,可以用以下()命令。 A: head -3 info B: cat -3 info C: tail -3 info D: more -3 info

  • 2022-06-08 问题

    代码“function info() { year = 1999; }; info(); console.log(year)”的结果是______。

    代码“function info() { year = 1999; }; info(); console.log(year)”的结果是______。

  • 2021-04-14 问题

    将字段User改为user需要编写| rename User user

    将字段User改为user需要编写| rename User user

  • 2022-05-28 问题

    在Redhat Enterprise Linux中,显示info文件的前4行,可以用以下()命令。 A: head 4 info B: cat -n 4 info C: head -n 4 infof D: more -n 4 info

    在Redhat Enterprise Linux中,显示info文件的前4行,可以用以下()命令。 A: head 4 info B: cat -n 4 info C: head -n 4 infof D: more -n 4 info

  • 2021-04-14 问题

    在【】位置填上正确的代码。下面的程序段定义struct student类型的结构体数组info,并将数组元素info[0]、info[1]、info[2]初始化为图8-2所示数据。6372477ee27026a2684980dcc101f994.jpg

    在【】位置填上正确的代码。下面的程序段定义struct student类型的结构体数组info,并将数组元素info[0]、info[1]、info[2]初始化为图8-2所示数据。6372477ee27026a2684980dcc101f994.jpg

  • 2022-06-11 问题

    已知,存在 QueryRunner对象 runner , SQL语句: String sql = "select * from user where id=?"; 下面操作中,能实现查询指定记录的选项是() A: User user=(User)runner.query(sql, new BeanListHandler(User.class), new Object[]{id}); B: User user=(User)runner.query(sql, new BeanHandler(User.class)); C: User user=(User)runner.query(sql, new BeanListHandler(User.class), id); D: User user=(User)runner.query(sql, new BeanHandler(User.class), new Object[]{id});

    已知,存在 QueryRunner对象 runner , SQL语句: String sql = "select * from user where id=?"; 下面操作中,能实现查询指定记录的选项是() A: User user=(User)runner.query(sql, new BeanListHandler(User.class), new Object[]{id}); B: User user=(User)runner.query(sql, new BeanHandler(User.class)); C: User user=(User)runner.query(sql, new BeanListHandler(User.class), id); D: User user=(User)runner.query(sql, new BeanHandler(User.class), new Object[]{id});

  • 2021-04-14 问题

    request.setAttribute("user","svse");session.setAttribute("user","bob");使用{user}则显示( )

    request.setAttribute("user","svse");session.setAttribute("user","bob");使用{user}则显示( )

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