语句ofstream f(″SALARY.DAT″,ios::app｜ios::binary);的功能是建立流对象f，试图打开文件SALARY.DAT 并与之连接，并且( )

以下语句错误的是（） A: SELECTrank，AVG（salary）FROMpeopleGROUPBYrankHAVINGAVG（salary）>1000 B: SELECTrank，AVG（salary）FROMpeopleHAVINGAVG（salary）>1000GROUPBYrank； C: SELECTAVG（salary）FROMpeopleGROUPBYrankHAVINGAVG（salary）>1000； D: SELECTrank，AVG（salary）FROMpeopleGROUPBYrankWHEREAVG（salary）>1000；

Finally I got my ____. A: salary raised B: risen salary C: salary rise D: salary to rise

下面哪个语句关于GROUP BY 和HAVING语句的使用是正确的？（) A: A.SELECT JOB_ID , DEPARTMENT_ID , AVG(SALARY)FROM EMPLOYEES GROUP BY JOB_IDHAVING AVG(SALARY) > 3000; B: B.SELECT JOB_ID , DEPARTMENT_ID , AVG(SALARY)FROM EMPLOYEES GROUP BY JOB_ID ,DEPARTMENT_IDHAVING AVG(SALARY) > 3000; C: C.SELECT JOB_ID , DEPARTMENT_ID , AVG(SALARY)FROM EMPLOYEES GROUP BY AVG(SALARY)HAVING AVG(SALARY) > 3000; D: D.SELECT JOB_ID , DEPARTMENT_ID , AVG(SALARY)FROM EMPLOYEES GROUP BY JOB_ID , DEPARTMENT_IDHAVING SALARY > 3000;

以下语句错误的是() A: LECT rank, AVG(salary) FROM people HAVING AVG(salary) > 1000 GROUP BY rank; B: SELECT rank, AVG(salary) FROM people GROUP BY rank HAVING AVG(salary) > 1000 C: SELECT rank, AVG(salary) FROM people HAVING AVG(salary) > 1000 GROUP BY rank; D: SELECT AVG(salary) FROM people GROUP BY rank HAVING AVG(salary) > 1000; E: SELECT rank, AVG(salary) FROM people GROUP BY rank WHERE AVG(salary) > 1000;

删除D盘根目录中所有DAT文件的命令是_____。 A: Kill "*.DAT" B: Kill "D:\*.DAT" C: Kill " D:\?.DAT" D: Kill D:\*.DAT

如果除了月工资，年终还发放全年工资的40%作为年终奖，计算每个公司的年收入( ) A: SELECT name, salary*(12+ salary*12*0.4) FROM job; B: SELECT name, salary*12+ 0.4 FROM job; C: SELECT name, salary*12+ salary*0.4 FROM job; D: SELECT name, salary*12+ salary*12*0.4 FROM job;

查询各类别的公司中比该类别最小工资高300元的公司、工资、类别 A: SELECT name, salary, type FROM job AS s1 WHERE salary > (SELECT min(salary) FROM job AS s2 WHERE s1.type = s2.type GROUP BY type) ; B: SELECT name, salary, type FROM job AS s1 WHERE salary > (SELECT min(salary) FROM job AS s2 WHERE s1.type = s2.type ) + 300; C: SELECT name, salary, type FROM job WHERE salary > 300; D: SELECT name, salary, type FROM job AS s1 WHERE salary > (SELECT min(salary) FROM job AS s2 WHERE s1.type = s2.type GROUP BY type) + 300;

salary

将CC2530的UART1串口接收到数据读到变量dat中的正确语句是（ ）。 A: dat = U1BUF; B: dat= U0BUF; C: dat= U1DBUF; D: dat= U0DBUF;