• 2022-06-19 问题

    关系模式Sailors(sid,lastname.firtname,age,ratring),其中lastname允许为空. 下面哪个语句能够查找出lastname属性值不为空的水手信息. A: SELECT * FROM SAILORS WHERE LASTNAME<>’NULL’ B: SELECT * FROM SAILORS WHERE LASTNAME<>NULL C: SELECT * FROM SAILORS WHERE LASTNAME IS not NULL D: SELECT * FROM SAILORS WHERE LASTNAME not LIKE ’NULL’

    关系模式Sailors(sid,lastname.firtname,age,ratring),其中lastname允许为空. 下面哪个语句能够查找出lastname属性值不为空的水手信息. A: SELECT * FROM SAILORS WHERE LASTNAME<>’NULL’ B: SELECT * FROM SAILORS WHERE LASTNAME<>NULL C: SELECT * FROM SAILORS WHERE LASTNAME IS not NULL D: SELECT * FROM SAILORS WHERE LASTNAME not LIKE ’NULL’

  • 2022-06-19 问题

    您如何把 "Persons" 表中 "LastName" 列的 "Gates" 改为 "Wilson" ? A: MODIFY Persons SET LastName='Wilson' WHERE LastName='Gates' B: UPDATE Persons SET LastName='Wilson' WHERE LastName='Gates' C: UPDATE Persons SET LastName='Wilson' INTO LastName='Gates' D: MODIFY Persons SET LastName='Wilson' INTO LastName='Gates'

    您如何把 "Persons" 表中 "LastName" 列的 "Gates" 改为 "Wilson" ? A: MODIFY Persons SET LastName='Wilson' WHERE LastName='Gates' B: UPDATE Persons SET LastName='Wilson' WHERE LastName='Gates' C: UPDATE Persons SET LastName='Wilson' INTO LastName='Gates' D: MODIFY Persons SET LastName='Wilson' INTO LastName='Gates'

  • 2022-06-19 问题

    通过 SQL,按字母顺序选取 Actor 表中 LastName 介于 Adams 和 Carter 的所有记录的表述正确的是( )。 A: SELECT * FROM Actor WHERE LastName BETWEEN 'Adams' AND 'Carter' B: SELECT * FROM Actor WHERE LastName>'Adams' AND LastName<'Carter' C: SELECT LastName>'Adams' AND LastName<'Carter' FROM Actor D: SELECT * FROM Actor WHERE LastName>'Adams' OR LastName<'Carter'

    通过 SQL,按字母顺序选取 Actor 表中 LastName 介于 Adams 和 Carter 的所有记录的表述正确的是( )。 A: SELECT * FROM Actor WHERE LastName BETWEEN 'Adams' AND 'Carter' B: SELECT * FROM Actor WHERE LastName>'Adams' AND LastName<'Carter' C: SELECT LastName>'Adams' AND LastName<'Carter' FROM Actor D: SELECT * FROM Actor WHERE LastName>'Adams' OR LastName<'Carter'

  • 2022-06-19 问题

    通过 SQL,您如何向 "Persons" 表中的 "LastName" 列插入 "Wilson" ? A: INSERT INTO Persons (LastName) VALUES ('Wilson') B: INSERT ('Wilson') INTO Persons (LastName) C: INSERT INTO Persons ('Wilson') INTO LastName D: INSERT Persons (LastName) VALUES ('Wilson')

    通过 SQL,您如何向 "Persons" 表中的 "LastName" 列插入 "Wilson" ? A: INSERT INTO Persons (LastName) VALUES ('Wilson') B: INSERT ('Wilson') INTO Persons (LastName) C: INSERT INTO Persons ('Wilson') INTO LastName D: INSERT Persons (LastName) VALUES ('Wilson')

  • 2022-06-14 问题

    通过 SQL,向 "Actor" 表中的 "LastName" 列插入 "Wilson"表述正确的是()。 A: INSERT INTO Actor (LastName) VALUES ('Wilson') B: INSERT INTO Actor ('Wilson') INTO LastName C: INSERT INTO Actor ('Wilson') INTO (LastName) D: INSERT ('Wilson') INTO Actor (LastName)

    通过 SQL,向 "Actor" 表中的 "LastName" 列插入 "Wilson"表述正确的是()。 A: INSERT INTO Actor (LastName) VALUES ('Wilson') B: INSERT INTO Actor ('Wilson') INTO LastName C: INSERT INTO Actor ('Wilson') INTO (LastName) D: INSERT ('Wilson') INTO Actor (LastName)

  • 2022-06-19 问题

    通过 SQL,您如何按字母顺序选取 Persons 表中 LastName 介于 Adams 和 Carter 之间(含其本身)的所有记录? A: SELECT * FROM Persons WHERE LastName BETWEEN 'Adams' AND 'Carter' B: SELECT * FROM Persons WHERE LastName>'Adams' AND LastName C: SELECT LastName>'Adams' AND LastName

    通过 SQL,您如何按字母顺序选取 Persons 表中 LastName 介于 Adams 和 Carter 之间(含其本身)的所有记录? A: SELECT * FROM Persons WHERE LastName BETWEEN 'Adams' AND 'Carter' B: SELECT * FROM Persons WHERE LastName>'Adams' AND LastName C: SELECT LastName>'Adams' AND LastName

  • 2022-06-19 问题

    下面代码的输出是什么?() functionPerson(firstName,lastName){ this.firstName=firstName; this.lastName=lastName; } constlydia=newPerson("Lydia","Hallie"); constsarah=Person("Sarah","Smith"); console.log(lydia); console.log(sarah); A: Person{firstName:"Lydia",lastName:"Hallie"}andundefined B: Person{firstName:"Lydia",lastName:"Hallie"}andPerson{firstName:"Sarah",lastName:"Smith"} C: Person{firstName:"Lydia",lastName:"Hallie"}and{} D: Person{firstName:"Lydia",lastName:"Hallie"}andReferenceError

    下面代码的输出是什么?() functionPerson(firstName,lastName){ this.firstName=firstName; this.lastName=lastName; } constlydia=newPerson("Lydia","Hallie"); constsarah=Person("Sarah","Smith"); console.log(lydia); console.log(sarah); A: Person{firstName:"Lydia",lastName:"Hallie"}andundefined B: Person{firstName:"Lydia",lastName:"Hallie"}andPerson{firstName:"Sarah",lastName:"Smith"} C: Person{firstName:"Lydia",lastName:"Hallie"}and{} D: Person{firstName:"Lydia",lastName:"Hallie"}andReferenceError

  • 2022-06-19 问题

    通过 SQL,您如何向 "Persons" 表中的 "LastName" 列插入 "Wilson" ? A: INSERT INTO Persons (LastName) VALUES ('Wilson') B: INSERT ('Wilson') INTO Persons (LastName) C: INSERT INTO Persons ('Wilson') INTO LastName

    通过 SQL,您如何向 "Persons" 表中的 "LastName" 列插入 "Wilson" ? A: INSERT INTO Persons (LastName) VALUES ('Wilson') B: INSERT ('Wilson') INTO Persons (LastName) C: INSERT INTO Persons ('Wilson') INTO LastName

  • 2022-06-19 问题

    在员工管理系统中,查询表employee表中所有员工的姓名,字段:id(int),firstname(varchar),lastname(varchar),以下sql语句正确的是()。 A: Select firstname +’.’+ lastname as ‘name’ from employee B: Select firstname +’.’+ lastname from employee C: Select ‘name’= firstname +’.’+ lastname from employee D: Select firstname,lastname from employee

    在员工管理系统中,查询表employee表中所有员工的姓名,字段:id(int),firstname(varchar),lastname(varchar),以下sql语句正确的是()。 A: Select firstname +’.’+ lastname as ‘name’ from employee B: Select firstname +’.’+ lastname from employee C: Select ‘name’= firstname +’.’+ lastname from employee D: Select firstname,lastname from employee

  • 2021-04-14 问题

    通过 SQL,在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是( )。? SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter'|SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'|SELECT FirstName='Jim', LastName='Carter' FROM Actor|SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter'

    通过 SQL,在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是( )。? SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter'|SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'|SELECT FirstName='Jim', LastName='Carter' FROM Actor|SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter'

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