对于关系模式S（Sno，Sname，Age，Dept），C（Cno，Cname，Teacher），SC（Sno，Cno，Score），下列查询结果相同的是（ ）。I．πSname((S) ∞σScore>60(SC)) II．πSname(σScore>60(S∞SC)) III．σScore>60 (πSname (S∞ SC)) IV．σScore>60 (πSname (S)∞ (SC)) A: I与II B: III与IV C: I与III D: II与IV

---Our monitor is really into Jay Zhou's music.He has at least_______ Jay Zhou's CDs.--- No wonder he can sing every single song of Jay Zhou's very well. A: three scores of B: three score of C: three score D: score of

下面代码的执行结果是（   ）。 String hql=“from Student s order by s.score desc”; Query query=session.createQuery(); Query.setFirstResult(1); Query.setMaxResult(10); return query.list();

Mary’s score on the test is the highest in her class; She____have studied very hard.

59（） A: everything is wrong B: Do you agree C: let’s total the score D: let’s do it E: we can do it F: Here is the answer sheet G: Here is your score H: the percentage is incorrect

关系SC(S，SNAME，SEX，SCORE，CNAME)，从关系SC中检索男生(SEX =M)并且成绩大于等于60的学生姓名，下述表示( )是正确的。 Ⅰ．ЛSNAME(σSCORE＞60□SEX=’M’(SC)) Ⅱ．σSCORE＞=60□SEX=’M’(ЛSNAME(SC)) Ⅲ．ЛSNAME(σSCORE＞=60□SEX=’M’(ЛSNAME，SCORE，SEX(SC))) A: Ⅰ和Ⅱ B: Ⅱ C: Ⅰ和Ⅲ D: Ⅰ

表stinfo和表scinfo，语句 SELECT stname, cno ,score FROM stinfo s LEFT JOIN scinfo sc ON s.stid=sc.stid 与语句 SELECT stname, cno,score FROM scinfo sc LEFT JOIN stinfo s ON s.stid=sc.stid 查询结果集完全相同

中国大学MOOC: 写出下面程序执行后的运行结果。#include <stdio.h>struct STU {char name[10];int num;int Score;};int main(){struct STU s[5]={{"YangSan",20041,703},{"LiSiGuo",20042,580},{"wangYin",20043,680},{"SunDan",20044,550},{"Penghua",20045,537}},*p[5],*t;int i,j;for(i=0;i<5;i++) p[i]=&s[i];for(i=0;i<4;i++)for(j=i+1;j<5;j++)if(p[i]->Score>p[j]->Score){ t=p[i]; p[i]=p[j]; p[j]=t;}printf("%d %d",s[1].Score,p[1]->Score); return 0;}

下面代码的输出结果是()。 <?php $score=87; if($score>=90 && $score<=100){$grade="优秀";} if($score>=80){$grade="良好";} if($score>=70){$grade="一般";} if($score>=60){$grade="及格";} else{$grade="不及格";} echo $grade; ?>

以下参数传递正确的是： A: def score(mid_score, end_score): ……score(88, 79) B: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(88, 79) C: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(end_score = 79, mid_score = 88) D: def score( *，mid_score, end_score, mid_rate＝0.4): ……score(mid_score = 88, end_score = 79,0.5)