• 2021-04-14 问题

    哪行代码会导致错误?()num=[5,4,3,[2],1]print(num[0])print(num[3][0])print(num[5])

    哪行代码会导致错误?()num=[5,4,3,[2],1]print(num[0])print(num[3][0])print(num[5])

  • 2021-04-14 问题

    智慧职教: 以下程序段实现的功能为:  num = int(input("please input a number:")) if num > 0:      print(num)  else:      print(-1*num)

    智慧职教: 以下程序段实现的功能为:  num = int(input("please input a number:")) if num > 0:      print(num)  else:      print(-1*num)

  • 2021-04-14 问题

    下面的代码输出什么?() num=7 if num>3: print(“3”) if num<5: print(“5”) if num==7: print(“7”)

    下面的代码输出什么?() num=7 if num>3: print(“3”) if num<5: print(“5”) if num==7: print(“7”)

  • 2021-04-14 问题

    下列程序的输出结果是() num = 27 count = 0 while num > 0: if num % 2 == 0: num /=2 elif num % 3 ==0: num /= 3 else: num -=1 count += 1 print (count)

    下列程序的输出结果是() num = 27 count = 0 while num > 0: if num % 2 == 0: num /=2 elif num % 3 ==0: num /= 3 else: num -=1 count += 1 print (count)

  • 2021-04-14 问题

    下面代码的运行结果是 def func(num): num += 1 a =10 func(a) print(a)

    下面代码的运行结果是 def func(num): num += 1 a =10 func(a) print(a)

  • 2022-05-26 问题

    阅读程序:private sub form_click()num=0do while num&lt;=3num=num+1print numloopend sub程序运行结果为:

    阅读程序:private sub form_click()num=0do while num&lt;=3num=num+1print numloopend sub程序运行结果为:

  • 2021-04-14 问题

    下面的代码输出什么?() nums=[5,4,3,2,1 print(num[1])

    下面的代码输出什么?() nums=[5,4,3,2,1 print(num[1])

  • 2022-05-29 问题

    有下列程序: num=6 while num>0: num=num-2 print(num)

    有下列程序: num=6 while num>0: num=num-2 print(num)

  • 2022-05-29 问题

    下列程序的输出结果是:num = 16 while Ture: if num &#91;12 and num &#93;=10: print (num) break num = num – 2 print (num) A: 10 B: 12 C: 14 D: 16

    下列程序的输出结果是:num = 16 while Ture: if num &#91;12 and num &#93;=10: print (num) break num = num – 2 print (num) A: 10 B: 12 C: 14 D: 16

  • 2022-06-16 问题

    以下哪个程序段是使用递归函数实现1到100求和 A: def product1(num): product=1 for i in range(1,num+1): product=product *i return productprint(product1(10)) B: def sum1(num): sum2=0 for i in range(1,num+1): sum2+=i return sum2 print(sum1(100)) C: def product2(num): if num==1: return 1 else: return num *product2(num-1)print(product2(10)) D: def sum_a(num1): if num1==1: return 1 else: return num1+sum_a(num1-1) print(sum_a(100))

    以下哪个程序段是使用递归函数实现1到100求和 A: def product1(num): product=1 for i in range(1,num+1): product=product *i return productprint(product1(10)) B: def sum1(num): sum2=0 for i in range(1,num+1): sum2+=i return sum2 print(sum1(100)) C: def product2(num): if num==1: return 1 else: return num *product2(num-1)print(product2(10)) D: def sum_a(num1): if num1==1: return 1 else: return num1+sum_a(num1-1) print(sum_a(100))

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