有以下代码,判断下面说法哪个是正确的( )。[br][/br]class Animal {[br][/br]public function run() {[br][/br]echo '奔跑';[br][/br]}[br][/br]}[br][/br]class Dog extends Animal {[br][/br]}[br][/br]$dog= new Dog();[br][/br]$dog->run();[br][/br]· A: $dog对象不能创建,因为没有任何成员<br>· B: 要访问run方法,需要创建Animal对象,通过Animal调用该方法<br>· C: 代码运行结果会在浏览器输出'奔跑'字样<br>· D: 代码运行错误

对于下列Dog类，下列叙述错误的是：class Dog{ Dog(){ } Dog(int m){ } Dog(double m){ } int Dog(int m){ return m; }} A: Dog(int m)与Dog(double m)是重载的构造方法； B: Dog(int m)与int Dog(int m)是重载的构造方法； C: Dog d=new Dog();对象d创建时会调用Dog()构造方法； D: Dog d=new Dog(10);对象d创建时会调用Dog(int m)构造方法；

If someone asks about the "breed"of your dog, they want to know the ________________. A: age of the dog B: sex of the dog C: type of dog D: name of the dog

class Animal { public Animal() { System.out.println("Animal!"); } } public class Dog extends Animal{ public Dog() { System.out.println("Dog!"); } public static void main(String[] args) { Dog dog=new Dog(); } }

public class Dog(){...}下列哪个选项可以是Dog类的构造方法 A: public Dog(){ } B: public void Dog(){ } C: public dog(){ } D: public void dog(){ }

对于下列Dog类，哪个叙述是错误的？ class Dog { Dog(int m){ } Dog(double m){ } int Dog(int m){ return 23; } void Dog(double m){ } }

______(Dog)dog is ______ useful animal.

中国大学MOOC: 下列Dog类，错误的描述是：class Dog{ Dog(int m){} Dog(double m){} int Dog(int m){ return 1;} void Dog(double m){}}

For example, a dog might be a family pet, a herding dog, a show dog, or a hunting dog.______

dog eat dog English: Chinese: