命名配合物[tex=10.429x1.357]Pd2QSjqnBMV71dGld0Tl9a048BCCljry4y8DyWzqY0ulamBNG93pGPCkqOVwHEaryRQXMVTZYlUt6bneskcxa/9Ih/ckxVCbbV4fGyitUKapoQ0dbBCTWkDToUGmDrjjxwK4qMnpOtvFnxwDY3IJYFVJ9iYi3VIlbxgNU9U/ajYnxOD5tF2QhgIi68n/nPG1[/tex]

‏在Solidworks软件中，仿真动画输出的影片格式为：‏ A: RM B: MP4 C: AVI D: NPG

在Solidworks软件中，仿真动画输出的影片格式为： A: RM B: MP4 C: AVI D: NPG

在Solidworks软件中，仿真动画输出的影片和图片的格式分别为？ A: RM和JPG B: MP4和PNG C: AVI和BMP D: NPG和PSD

习题 图 (a) 所示木梁受一可移动的荷载 F=40 kN 作用。已知许用弯曲正应力 [tex=5.071x1.357]eLvAvdNizy+MhhiVk2luuCLiCAcc9hBCobCZa8NE9QE=[/tex], 许用切变力[tex=5.643x1.357]YLfaDGBRngnU2JNEfo/Npg==[/tex]。 木梁的横截面为矩形, 其高宽比 [tex=3.786x2.429]BrpgBeHoQ0x6UxcEbVs6af6DOKeT0Xn812AbjJo4lGA=[/tex]。试选择梁的截面尺寸。[img=509x202]17e0f54143ed4c2.png[/img]

for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是：__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常

【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1

for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是（）。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1

下列哪个码片序列不能用于CDMA通信 A: ( -1 -1 -1 +1 +1 -1 +1 +1 ) B: ( -1 -1 +1 -1 +1 +1 +1 -1 ) C: ( -1 +1 -1 +1 +1 -1 -1 -1 ) D: ( -1 +1 -1 -1 -1 -1 +1 -1 )

请仔细观察下面行列式的计算过程，如果四个等号都理解了，请选择A，否则请选择B。 | a 1 1 1 1 | |a＋4 a＋4 a＋4 a＋4 a＋4| | 1 a 1 1 1 | | 1 a 1 1 1 | | 1 1 a 1 1 |= | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 a | | 1 1 1 1 1 | | 1 a 1 1 1 | =(a＋4) | 1 1 a 1 1 | | 1 1 1 a 1 | | 1 1 1 1 a | | 1 1 1 1 1 | | 0 a–1 0 0 0 | =(a＋4) | 0 0 a–1 0 0 | | 0 0 0 a–1 0 | | 0 0 0 0 a–1 | =(a＋4)(a–1)^4