• 2022-06-15 问题

    [tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex] 二阶可导, [tex=6.0x1.357]7uK7DvrGdGMFo+AgMn8Okw==[/tex], 则 [tex=1.571x1.357]AlvHPx/LzcsIUKOnHor/SA==[/tex][input=type:blank,size:6][/input], [tex=1.786x1.357]eE9dXkpN2effVrNkAbXJmClGvj/EWFaJcsc0DJCFeuY=[/tex][input=type:blank,size:6][/input].

    [tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex] 二阶可导, [tex=6.0x1.357]7uK7DvrGdGMFo+AgMn8Okw==[/tex], 则 [tex=1.571x1.357]AlvHPx/LzcsIUKOnHor/SA==[/tex][input=type:blank,size:6][/input], [tex=1.786x1.357]eE9dXkpN2effVrNkAbXJmClGvj/EWFaJcsc0DJCFeuY=[/tex][input=type:blank,size:6][/input].

  • 2022-06-03 问题

    设函数 [tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex] 存在二阶导数, [tex=4.143x1.357]BJMhsnWWy+b17IpjqvqyPw==[/tex], 则 [tex=1.786x1.357]eE9dXkpN2effVrNkAbXJmClGvj/EWFaJcsc0DJCFeuY=[/tex] 未知类型:{'options': ['[tex=9.286x2.357]37TQb255fZowyaPzOHy4h3kVoXLcN3AorUF5hsxVx2tKeBSQZcBcFcNRBJoTm6MoQBsBiLI2Oc5sRpMzRci3I30tKrEv3un5aCTaPPW+gPg=[/tex]', '[tex=9.286x2.357]37TQb255fZowyaPzOHy4h3kVoXLcN3AorUF5hsxVx2sZsn4pmMUHtaGdQRsv/1rABr3T3aUTgvVCm4Hf2cFIdjoBb49jpWrHX/UnwbEa9C4=[/tex]', '[tex=9.857x2.357]37TQb255fZowyaPzOHy4h+4K/AFwpfmhpziRDI4J6k5lkjegV25r7h2t0tDlZfSpsAXLO877+/YnmP1G4HMb9MtX0Jmb/aA8I1I34ankEUg=[/tex]', '[tex=9.857x2.357]37TQb255fZowyaPzOHy4h+4K/AFwpfmhpziRDI4J6k7wp5o/zCD4jGKLPJ1+dJ9SLRdhdPBKenYHwz9MoVqCXm2vFx4VTqLhzxg9eMB5rb0=[/tex]'], 'type': 102}

    设函数 [tex=1.857x1.357]bZ4KhrFbnCaidqbMGQZfww==[/tex] 存在二阶导数, [tex=4.143x1.357]BJMhsnWWy+b17IpjqvqyPw==[/tex], 则 [tex=1.786x1.357]eE9dXkpN2effVrNkAbXJmClGvj/EWFaJcsc0DJCFeuY=[/tex] 未知类型:{'options': ['[tex=9.286x2.357]37TQb255fZowyaPzOHy4h3kVoXLcN3AorUF5hsxVx2tKeBSQZcBcFcNRBJoTm6MoQBsBiLI2Oc5sRpMzRci3I30tKrEv3un5aCTaPPW+gPg=[/tex]', '[tex=9.286x2.357]37TQb255fZowyaPzOHy4h3kVoXLcN3AorUF5hsxVx2sZsn4pmMUHtaGdQRsv/1rABr3T3aUTgvVCm4Hf2cFIdjoBb49jpWrHX/UnwbEa9C4=[/tex]', '[tex=9.857x2.357]37TQb255fZowyaPzOHy4h+4K/AFwpfmhpziRDI4J6k5lkjegV25r7h2t0tDlZfSpsAXLO877+/YnmP1G4HMb9MtX0Jmb/aA8I1I34ankEUg=[/tex]', '[tex=9.857x2.357]37TQb255fZowyaPzOHy4h+4K/AFwpfmhpziRDI4J6k7wp5o/zCD4jGKLPJ1+dJ9SLRdhdPBKenYHwz9MoVqCXm2vFx4VTqLhzxg9eMB5rb0=[/tex]'], 'type': 102}

  • 2021-04-14 问题

    238.已知二值医学图像IA=[0()0()0()0()0;()0()0()1()1()0;()0()0()1()1()0;()0()0()0()0()0;()0()0()0()0()0],结构元素IB=[0()1()0;()1()1()1;()0()1()0],()结构元素IB对应的坐标是[(-1,-1)(-1,0)(-1,1):(0,-1)(0,0)(0,1);(1,-1)(1,0)(1,1)],则用结构元素IB对图像IA腐蚀后的图像IC是()。A.()[0()0()0()0()0;()0()0()0()0()0;()0()0()0()0()0;()0()0()0()0()0;()0()0()0()0()0]B.()[0()0()0()0()0;()0()0()11()0;()0()0()0()1()0;()0()0()0()0()0;()0()0()0()0()0]C.()[0()0()0()0()0;()0()0()1()0()0;()0()0()1()1()0;()0()0()0()0()0;()0()0()0()0()0]D.()[0()0()0()0()0;()0()0()0()1()0;()0()0()0()1()0;()0()0()0()0()0;()0()0()0()0()0]

    238.已知二值医学图像IA=[0()0()0()0()0;()0()0()1()1()0;()0()0()1()1()0;()0()0()0()0()0;()0()0()0()0()0],结构元素IB=[0()1()0;()1()1()1;()0()1()0],()结构元素IB对应的坐标是[(-1,-1)(-1,0)(-1,1):(0,-1)(0,0)(0,1);(1,-1)(1,0)(1,1)],则用结构元素IB对图像IA腐蚀后的图像IC是()。A.()[0()0()0()0()0;()0()0()0()0()0;()0()0()0()0()0;()0()0()0()0()0;()0()0()0()0()0]B.()[0()0()0()0()0;()0()0()11()0;()0()0()0()1()0;()0()0()0()0()0;()0()0()0()0()0]C.()[0()0()0()0()0;()0()0()1()0()0;()0()0()1()1()0;()0()0()0()0()0;()0()0()0()0()0]D.()[0()0()0()0()0;()0()0()0()1()0;()0()0()0()1()0;()0()0()0()0()0;()0()0()0()0()0]

  • 2022-06-19 问题

    ‍对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码,结果是( )。‌ A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1

    ‍对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码,结果是( )。‌ A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1

  • 2022-11-04 问题

    执行eye(3,5)后,其结果是( ) A: ans = <br> 1 0 0 0 1 0 0 0 1 B: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 C: ans = <br> 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 D: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0

    执行eye(3,5)后,其结果是( ) A: ans = <br> 1 0 0 0 1 0 0 0 1 B: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0 0 0 0 1 C: ans = <br> 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 D: ans = <br> 1 0 0 0 0 0 1 0 0 0 0 0 1 0 0

  • 2021-04-14 问题

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]]

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]]

  • 2021-04-14 问题

    根据下列真值表,采用case语句描述一个8-3编码器,输入信号:x[7..0]时,输出y[2..0]。 输入X 输出Y X0 X1 X2 X3 X4 X5 X6 X7 Y2 Y1 Y0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 1 0 0 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 1 1 1 1

    根据下列真值表,采用case语句描述一个8-3编码器,输入信号:x[7..0]时,输出y[2..0]。 输入X 输出Y X0 X1 X2 X3 X4 X5 X6 X7 Y2 Y1 Y0 1 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 1 1 0 0 0 0 1 0 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 1 0 0 0 0 0 0 1 0 1 1 0 0 0 0 0 0 0 0 1 1 1 1

  • 2021-04-14 问题

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]] 提示:可以先创建全为0或者全为1的数组,再通过索引和切片机制进行修改

    编写程序,创建下列10*10的数组,数组边界全为1,里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]] 提示:可以先创建全为0或者全为1的数组,再通过索引和切片机制进行修改

  • 2022-06-16 问题

    以下HDB3码中,哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……

    以下HDB3码中,哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……

  • 2022-06-16 问题

    对信码1000100100001000011000011进行HDB3编码,结果可能是( )。 A: -1 0 0 0 +1 0 0 -1 0 0 0 -V +1 0 0 0 +V -1 +1 -B 0 0 -V +1 -1 B: +1 0 0 0 -1 0 0 +1 0 0 0 +V -1 0 0 0 -V +1 -1 +B 0 0 +V -1 +1 C: +1 0 0 0 -1 0 0 +1 0 0 0 +1 -1 0 0 0 -1 +1 -1 +1 0 0 +1 -1 +1 D: -1 0 0 0 +1 0 0 -1 0 0 0 +V +1 0 0 0 +V -1 +1 +B 0 0 -V +1 -1

    对信码1000100100001000011000011进行HDB3编码,结果可能是( )。 A: -1 0 0 0 +1 0 0 -1 0 0 0 -V +1 0 0 0 +V -1 +1 -B 0 0 -V +1 -1 B: +1 0 0 0 -1 0 0 +1 0 0 0 +V -1 0 0 0 -V +1 -1 +B 0 0 +V -1 +1 C: +1 0 0 0 -1 0 0 +1 0 0 0 +1 -1 0 0 0 -1 +1 -1 +1 0 0 +1 -1 +1 D: -1 0 0 0 +1 0 0 -1 0 0 0 +V +1 0 0 0 +V -1 +1 +B 0 0 -V +1 -1

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