同时给内存变量a1和a2赋值的正确命令是（）。 A: a1，a2=0 B: a1=0，a2=0 C: store0toa1，a2 D: store0，0toa1，a2

以下赋值语句执行后，变量A的值不是日期型的是（） A: A=DATE（） B: A={^2008-4-5} C: A=CTOD（“4/5/2008”） D: STORE（4/5/2008）TOA

在FoxPro命令窗口中输入下列命令： Store .f. to r ? r 执行后显示的结果是（ ）。 A: F B: T C: 0 D: 1

执行下列程序： Set talk off Store .T. to x Store 0 to y Do while x y=y+1 if int（y/3）=y/3 ??y Else Loop Endif If y>20 Store .F. to x Endif Enddo Set talk on

以下HDB3码中，哪些可以确定其中有误码 A: +1 0 0 0 -1 0 +1 -1 +1 0 0 +1 0 -1 +1 -1 0 0 -1 +1…… B: +1 0 0 -1 +1 0 0 0 +1 -1 0 0 -1 0 0 0 +1 0 0 +1 -1…… C: -1 0 0 0 -1 0 +1 0 0 0 +1 -1 +1 0 0 +1 0 0 -1 +1…… D: -1 0 +1 0 0 0 -1 +1 0 0 0 +1 -1 +1 -1 0 0 -1 +1 0 -1……

‍对HDB3码-1000+100-1000-1+1000+1-1+1-100-1+1-1进行译码，结果是（ ）。‌ A: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 0 1 1 0 0 0 0 1 1 B: 1 0 0 0 1 0 0 1 0 0 0 1 1 0 0 0 0 1 1 0 0 0 0 0 1 C: 1 0 1 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 1 0 0 0 0 1 1 D: 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 0 0 1 1

编写程序，创建下列10*10的数组，数组边界全为1，里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]]

百货大赛 A: department store B: convenience store C: chain store

编写程序，创建下列10*10的数组，数组边界全为1，里面全为0。 [[1 1 1 1 1 1 1 1 1 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 0 0 0 0 0 0 0 0 1] [1 1 1 1 1 1 1 1 1 1]] 提示：可以先创建全为0或者全为1的数组，再通过索引和切片机制进行修改

1 I ___________ this store ________ closed. A: think, is B: thought, is C: think, was D: thought, was