• 2022-05-31 问题

    以下类方法定义正确的是() A: class Student: fav=("唱歌","跳舞","绘画") def showFav(cls): for item in cls.fav: print(item) B: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in fav: print(item) C: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in cls.fav: print(item) D: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(): for item in fav: print(item)

    以下类方法定义正确的是() A: class Student: fav=("唱歌","跳舞","绘画") def showFav(cls): for item in cls.fav: print(item) B: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in fav: print(item) C: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in cls.fav: print(item) D: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(): for item in fav: print(item)

  • 2022-06-16 问题

    有表song(id,song_name,album,play_count,fav_count)分别表示歌曲的主键id、歌曲名、专辑名、播放次数和收藏次数,以下与order by相关的sql错误的是: A: select * from song order by play_count asc; B: select * from song order by (play_count + fav_count) asc; C: select * from song order by fav_count desc where play_count > 5; D: select * from song order by id,play_count asc,fav_count desc;

    有表song(id,song_name,album,play_count,fav_count)分别表示歌曲的主键id、歌曲名、专辑名、播放次数和收藏次数,以下与order by相关的sql错误的是: A: select * from song order by play_count asc; B: select * from song order by (play_count + fav_count) asc; C: select * from song order by fav_count desc where play_count > 5; D: select * from song order by id,play_count asc,fav_count desc;

  • 2022-05-31 问题

    以下类方法定义正确的是() A: class Student: fav=("唱歌","跳舞","绘画") def showFav(cls): for item in cls.fav: print(item) B: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in fav: print(item) C: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in cls.fav: print(item) D: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(): for item in fav: print(item)

    以下类方法定义正确的是() A: class Student: fav=("唱歌","跳舞","绘画") def showFav(cls): for item in cls.fav: print(item) B: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in fav: print(item) C: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(cls): for item in cls.fav: print(item) D: class Student: fav=("唱歌","跳舞","绘画") @classmethod def showFav(): for item in fav: print(item)

  • 2022-06-07 问题

    count = 0while count < 5: print( count) count = count + 2print( “Over!")

    count = 0while count < 5: print( count) count = count + 2print( “Over!")

  • 2022-06-07 问题

    阅读以下程序public class Count{static int count;int number;public Count(){count = count + 1;number = count;}}class Test{public static void Main(){Count a = new Count();Count b = new Count();Count c = new Count();}}程序运行后,对象a的count值是() A: 0 B: 1 C: 2 D: 3

    阅读以下程序public class Count{static int count;int number;public Count(){count = count + 1;number = count;}}class Test{public static void Main(){Count a = new Count();Count b = new Count();Count c = new Count();}}程序运行后,对象a的count值是() A: 0 B: 1 C: 2 D: 3

  • 2021-04-14 问题

    count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")

    count = 0 while count < 5: print (count, " 小于 5") count = count + 1 else: print (count, " 大于或等于 5")

  • 2022-07-23 问题

    下列if语句中,程序风格最规范的是()。 A: if (count >;= 100) count = 0; B: if (count >;= 100) {count = 0;} C: if (count >;= 100)count = 0; D: if (count >;= 100){count = 0;}

    下列if语句中,程序风格最规范的是()。 A: if (count >;= 100) count = 0; B: if (count >;= 100) {count = 0;} C: if (count >;= 100)count = 0; D: if (count >;= 100){count = 0;}

  • 2022-06-16 问题

    有表song(id,song_name,album,play_count,fav_count)分别表示歌曲的主键id、歌曲名、专辑名、播放次数和收藏次数。要求查询超过两首歌的专辑与其歌曲数,并且按专辑名排序;有同学给出如下sql语句: select id,count(*) from song order by albumgroup[br][/br]by album having count(*)>2 ; 这个sql错误的地方是: A: order by 后面跟group by语句 B: album没有出现在select语句中 C: 在having条件中使用了count(*) D: 这个sql语句没有错误

    有表song(id,song_name,album,play_count,fav_count)分别表示歌曲的主键id、歌曲名、专辑名、播放次数和收藏次数。要求查询超过两首歌的专辑与其歌曲数,并且按专辑名排序;有同学给出如下sql语句: select id,count(*) from song order by albumgroup[br][/br]by album having count(*)>2 ; 这个sql错误的地方是: A: order by 后面跟group by语句 B: album没有出现在select语句中 C: 在having条件中使用了count(*) D: 这个sql语句没有错误

  • 2022-06-07 问题

    给定一个Java程序的代码如下所示,则编译运行后,输出结果是 ( )。 public class Test { int count = 9; public void count() { System.out.println("count=" + count++); } A: blic static void main(String args[]) new Test().count(); new Test().count();}} B: count=9 count=9 C: count=10 count=9 D: count=10 count=10 E: count=9 count=10

    给定一个Java程序的代码如下所示,则编译运行后,输出结果是 ( )。 public class Test { int count = 9; public void count() { System.out.println("count=" + count++); } A: blic static void main(String args[]) new Test().count(); new Test().count();}} B: count=9 count=9 C: count=10 count=9 D: count=10 count=10 E: count=9 count=10

  • 2022-06-07 问题

    使用while 语句实现打印出1至10.count = 1while ( ) print (count) count = count + 1 A: count B: True C: count D: count

    使用while 语句实现打印出1至10.count = 1while ( ) print (count) count = count + 1 A: count B: True C: count D: count

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