LDI0.0;SQ0.0,2;执行该程序后Q0.0,Q0.1,Q0.2被置1。()
LDI0.0;SQ0.0,2;执行该程序后Q0.0,Q0.1,Q0.2被置1。()
循环队列 SQ 采用数组空间 SQ.base[0, n-1] 存放其元素值,已知头指针 front 指向队列头元素,尾指针 rear 指向队列尾元素的下一个位置,则队列 SQ 为满的判断条件是( )。 A: front == rear % n B: front == ( rear + 1 ) % n C: front == rear % n - 1 D: front == rear % ( n – 1 )
循环队列 SQ 采用数组空间 SQ.base[0, n-1] 存放其元素值,已知头指针 front 指向队列头元素,尾指针 rear 指向队列尾元素的下一个位置,则队列 SQ 为满的判断条件是( )。 A: front == rear % n B: front == ( rear + 1 ) % n C: front == rear % n - 1 D: front == rear % ( n – 1 )
设数组data[0…m]作为循环队列sq的存储空间,front为队头指针,rear为队尾指针,则执行出队操作的语句为()。 A: sq↑.front:=sq↑.front+1; B: sq↑.front:=(sq↑.front+1)%maxsize; C: sq↑.rear:=(sq↑.rear+1)%maxsize; D: sq↑.front:=(sq↑.front+1)%(maxsize+1);
设数组data[0…m]作为循环队列sq的存储空间,front为队头指针,rear为队尾指针,则执行出队操作的语句为()。 A: sq↑.front:=sq↑.front+1; B: sq↑.front:=(sq↑.front+1)%maxsize; C: sq↑.rear:=(sq↑.rear+1)%maxsize; D: sq↑.front:=(sq↑.front+1)%(maxsize+1);
初始化一个空间大小为5的循环队列Sq后,Sq->front的值是()。 A: 0 B: 不定 C: 不再改变 D: 1
初始化一个空间大小为5的循环队列Sq后,Sq->front的值是()。 A: 0 B: 不定 C: 不再改变 D: 1
CPU224XP型PLC,执行指令“SQ0.3,2”后,下列哪些位的状态为“1”() A: Q0.1 B: Q0.2 C: Q0.3 D: Q0.4 E: Q0.5
CPU224XP型PLC,执行指令“SQ0.3,2”后,下列哪些位的状态为“1”() A: Q0.1 B: Q0.2 C: Q0.3 D: Q0.4 E: Q0.5
设数组 data[0…m]作为循环队列 SQ 的存储空间, front 为队头指针, rear为队尾指针,则执行出队操作的语句为() A: front:=front 1 B: front:=(front 1) mod m C: .front:=(front 1) mod (m 1) D: sq1. front: =(sq1. front+1) %(maxsize+1);
设数组 data[0…m]作为循环队列 SQ 的存储空间, front 为队头指针, rear为队尾指针,则执行出队操作的语句为() A: front:=front 1 B: front:=(front 1) mod m C: .front:=(front 1) mod (m 1) D: sq1. front: =(sq1. front+1) %(maxsize+1);
读电气原理图,分析下列问题:(1)电气原理图中电动机有几种工作状态?(2)电气原理图中通过什么电器实现什么保护?(3)说明SA、SQ的作用。
读电气原理图,分析下列问题:(1)电气原理图中电动机有几种工作状态?(2)电气原理图中通过什么电器实现什么保护?(3)说明SA、SQ的作用。
for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常
for i in range(b.max_row): for j in range(b.max_column): print(b.cell(row=i,column=j).value)上面语句运行的结果是:__________。 A: 1 1 1 1 1 1 1 1 1 1 B: 1111111111 C: 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 D: 出现异常
【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1
【单选题】CDMA通信的基站,假定基站A的码片序列是+1 +1 +1 -1 -1 +1 -1 -1,基站发射bit为101时,实际发射的信号是 A. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 B. +1 +1 +1 -1 -1 +1 -1 -1 –1 –1 –1 +1 +1 –1 +1 +1 +1 +1 +1 -1 -1 +1 -1 -1 C. +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 +1 +1 +1 -1 -1 +1 -1 -1 D. –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1 –1 –1 –1 +1 +1 –1 +1 +1
for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是()。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1
for i in range(1,11): for j in range(1,11): b.cell(row=i,column=j).value=1 #b是一个工作表对象for i in range(1,11): for j in range(1,11): print(b.cell(row=i,column=j).value,end=" ") print()上面程序代码运行的结果是()。 A: 1 B: 1 1 1 1 1 1 1 1 1 1 C: 1111111111 D: 1 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 11 1 1 1 1 1 1 1 1 1