• 2021-04-14 问题

    How long haveyou _______ here?1

    How long haveyou _______ here?1

  • 2021-04-14 问题

    【单选题】—Haveyou got any idea for the summer vacation? —Idon’t mind where we go ______ there’s sun, sea and beach. A. as if B. as long as C. now that D. in order that

    【单选题】—Haveyou got any idea for the summer vacation? —Idon’t mind where we go ______ there’s sun, sea and beach. A. as if B. as long as C. now that D. in order that

  • 2022-06-06 问题

    B.Nowwatchthevideoagainandthencompletethefollowingconversation.Michael:HiShelley.meetingyouhere!Shelley:youhere!Whatareyoudoinginthisplace?Michael:I’mexploringonmybike.Shelley:Cool.Youlookgreat!Michael:Youtoo.Ididn’tknowyougot.Shelley:Yeah,Idid.Somaybewecouldtogether.Michael:You’reon.Shelley:Ihaven’tseenyou.Where’veyoubeenhidingyourself?Michael:Oh,I’vebeenbusystudyingChinese.Shelley:Haveyou?!Tolearnaforeignlanguageistolearnitsculture.Michael:Youbet.That’swhyI’mhere.Shelley:It’slunchtime.Howaboutforlunch?Michael:That’s.Howaboutthatrestaurantbytheriver?Shelley:Sure,let’s.

    B.Nowwatchthevideoagainandthencompletethefollowingconversation.Michael:HiShelley.meetingyouhere!Shelley:youhere!Whatareyoudoinginthisplace?Michael:I’mexploringonmybike.Shelley:Cool.Youlookgreat!Michael:Youtoo.Ididn’tknowyougot.Shelley:Yeah,Idid.Somaybewecouldtogether.Michael:You’reon.Shelley:Ihaven’tseenyou.Where’veyoubeenhidingyourself?Michael:Oh,I’vebeenbusystudyingChinese.Shelley:Haveyou?!Tolearnaforeignlanguageistolearnitsculture.Michael:Youbet.That’swhyI’mhere.Shelley:It’slunchtime.Howaboutforlunch?Michael:That’s.Howaboutthatrestaurantbytheriver?Shelley:Sure,let’s.

  • 2021-04-14 问题

    求解常微分方程组<img src="http://img1.ph.126.net/B8qMozAYz7oEzmWV3LBSvg==/6597340246519736485.png" />, 应用的语句是? DSolve[{x'[t]+y[t]==Cos[t],y'[t]+x[t]==Sin[t]},{x,y},t]|DSolve[{x'[t]+y[t]==Cos[t],y'[t]+x[t]==Sin[t]},x[t],y[t],t]|DSolve[{x'[t]+y[t]==Cos[t],y'[t]+x[t]==Sin[t]},{x[t],y[t]},t]|DSolve[x'[t]+y[t]=Cos[t],y'[t]+x[t]=Sin[t],{x[t],y[t]},t]

    求解常微分方程组<img src="http://img1.ph.126.net/B8qMozAYz7oEzmWV3LBSvg==/6597340246519736485.png" />, 应用的语句是? DSolve[{x'[t]+y[t]==Cos[t],y'[t]+x[t]==Sin[t]},{x,y},t]|DSolve[{x'[t]+y[t]==Cos[t],y'[t]+x[t]==Sin[t]},x[t],y[t],t]|DSolve[{x'[t]+y[t]==Cos[t],y'[t]+x[t]==Sin[t]},{x[t],y[t]},t]|DSolve[x'[t]+y[t]=Cos[t],y'[t]+x[t]=Sin[t],{x[t],y[t]},t]

  • 2021-04-14 问题

    下述真值表表示的命题是。 Input Output p q r T T T T T T F F T F T T T F F T F T T T F T F T F F T T F F F T

    下述真值表表示的命题是。 Input Output p q r T T T T T T F F T F T T T F F T F T T T F T F T F F T T F F F T

  • 2022-07-26 问题

    图示系统的微分方程为( )[img=808x247]17de73b60010c18.png[/img] A: y''(t)+3y'(t)+2y(t)=4f'(t)+f(t) B: y''(t)+2y'(t)+3y(t)=4f'(t)+f(t) C: 4y'(t)+y(t)=f''(t)+3f'(t)+2f(t) D: y''(t)+3y'(t)+2y(t)=f'(t)+4f(t)

    图示系统的微分方程为( )[img=808x247]17de73b60010c18.png[/img] A: y''(t)+3y'(t)+2y(t)=4f'(t)+f(t) B: y''(t)+2y'(t)+3y(t)=4f'(t)+f(t) C: 4y'(t)+y(t)=f''(t)+3f'(t)+2f(t) D: y''(t)+3y'(t)+2y(t)=f'(t)+4f(t)

  • 2022-06-19 问题

    求微分方程[img=261x61]17da6536c0cca5d.png[/img]的通解; ( ) A: C18*cos(t) - C20*sin(t) - C19*t*cos(t) - C21*t*sin(t) B: C18*cos(t) + C20*sin(t) - C19*t*cos(t) - C21*t*sin(t) C: C18*cos(t) + C20*sin(t) + C19*t*cos(t) + C21*t*sin(t) D: -C18*cos(t) + C20*sin(t) + C19*t*cos(t) + C21*t*sin(t)

    求微分方程[img=261x61]17da6536c0cca5d.png[/img]的通解; ( ) A: C18*cos(t) - C20*sin(t) - C19*t*cos(t) - C21*t*sin(t) B: C18*cos(t) + C20*sin(t) - C19*t*cos(t) - C21*t*sin(t) C: C18*cos(t) + C20*sin(t) + C19*t*cos(t) + C21*t*sin(t) D: -C18*cos(t) + C20*sin(t) + C19*t*cos(t) + C21*t*sin(t)

  • 2022-05-28 问题

    在t检验中,α水平上的否定域是: A: (-∞,tα]和[tα,+∞) B: (- tα,+tα) C: (-∞,tα]和(- tα,+tα) D: [tα,+∞)和(- tα,+tα)

    在t检验中,α水平上的否定域是: A: (-∞,tα]和[tα,+∞) B: (- tα,+tα) C: (-∞,tα]和(- tα,+tα) D: [tα,+∞)和(- tα,+tα)

  • 2022-07-29 问题

    在()温度范围内,玻璃态聚合物才具有典型的应力-应变曲线。 A: T﹤T﹤T B: T﹤T﹤T﹤T C: T﹤T﹤T﹤T

    在()温度范围内,玻璃态聚合物才具有典型的应力-应变曲线。 A: T﹤T﹤T B: T﹤T﹤T﹤T C: T﹤T﹤T﹤T

  • 2022-06-19 问题

    下列等式不成立的是_____。 A: f(t)δ’(t)=f(0)δ’(t) B: f(t)δ(t)=f(0)δ(t) C: f(t)*δ’(t)=f ’(t) D: f(t)*δ(t)=f(t)

    下列等式不成立的是_____。 A: f(t)δ’(t)=f(0)δ’(t) B: f(t)δ(t)=f(0)δ(t) C: f(t)*δ’(t)=f ’(t) D: f(t)*δ(t)=f(t)

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