Student类中存在String类型name属性,下列Student类的构造方法中,哪个是正确的？ A: Student(String name){} B: Student(String name) C: Student(name)() D: NewStudent (String name){}

以下代码中，实例方法定义正确的是（） A: class Student: def setName(self,name): self.name=name B: class Student: def setName(name): self.name=name C: class Student: def setName(self): self.name=name D: class Student: def setName(name,self): self.name=name

表student中的包含两个字段，整型的id，字符串型的name。只显示表student中name列记录的SQL语句正确的是（） A: select name from student B: select * from student C: select from name in student D: select name

下面哪一个是JSON数据？（） A: ｛name："xiaoming"，age，"student"｝ B: ｛"name"："xiaoming"，"age"："student"｝ C: ｛"xiaoming"，"student"｝ D: ["xiaoming"，"student"]

若想查询student表中name为空值的记录，则正确的SQL语句是（ ）。 A: SELECT * FROM student WHERE name = NULL; B: SELECT * FROM student WHERE name like NULL; C: SELECT * FROM student WHERE name = 'NULL'; D: SELECT * FROM student WHERE name is NULL;

若想查询student表中name为空值的记录，则正确的SQL语句是（1.0分） A: select * from student where name = null; B: select * from student where name link null; C: select * from student where name = 'null'; D: select * from student where name is null;

以下变量定义，错误的是： A: struct student{int num, char name[20];} s; B: struct {int num, char name[20];} s; C: struct student{int num, char name[20];}; struct student s; D: struct student{int num, char name[20];} ; student s

下列声明结构体变量错误的是（ ） A: A．struct student 　{　int no; char name[16]; ｝st1,st2; B: B． struct student｛ int no;char name[16];｝;struct student st1,st2; C: C．struct student { int no; char name[16]; }; struct st1,st2; D: D．struct student{ int no;char name[16]; };student st1,st2;

以下有关类的声明，正确的是 A: class Student(object) def __init__(self, name, score): self.name = name self.score = score B: class Student(object) def __init__(self, name, score) self.name = name self.score = score C: class Student(object)： def __init__(self, name, score): self.name = name self.score = score D: class Student(object)： def __int__(self, name, score): self.name = name self.score = score

已知 student 表有姓名字段 name ,并且存在 name 为’sun%er’的记录。下列选项中,以匹配“ sun%er ”字段值的 SQL 语句是 A: SELECT * FROM student WHERE name LIKE ‘sun%er’; B: SELECT * FROM student WHERE name LIKE ‘%%%’; C: SELECT * FROM student WHERE name LIKE '%\%%'; D: SELECT * FROM student WHERE name =‘sun%er’;