设某顺序表中第一个元素的地址是Base,每个结点占m个单元,则第i个结点的地址为()。 A: Base-i×m B: Base+(i+1)×m C: Base+i×m D: Base+(i-1)×m

（8-2）有如下类定义，为类Base中的变量a增加修饰符是合法的。 public class Base{ int a=8; public Base( int i ) { a = i; } }

当你编译运行下列程序代码,会得到什么结果? 。 private class Base{ Base(){ int i = 100; System.out.println(i); } } public class Pri extends Base{ static int i = 200; public static void main(String argv[]){ Pri p = new Pri(); System.out.println(i); } }

如何能使程序调用Base类的构造方法输出"base constructor"; class Base{ Base(int i){ System.out.println("base constructor"); } Base(){  } } public class Sup extends Base{ public static void main(String argv[]){ Sup s= new Sup(); //One } Sup() { //Two } public void derived() { //Three } }

给出以下代码，请问插入以下哪些语句可以使程序编译通过？（ ）class Base{public Base(int i){}}public class Example extend Base{public static void main (String arg[]){Example e = new Example(10);}Example(int i){Super(i);}Exanple(String s, int i){this(i);//插入代码处}}请选择一个正确答案： A: Example d = new Example(); B: Super(); C: This(“Hello”,10); D: Base b = ne Base(10);

判定一个顺序栈S为空的条件是()。 A: ! B: top C: D: base== E: top F: ! G: base H: I: base!= J: top

把从键盘上输入的十进制数(long型)以二进制到十六进制形式输出。请填空。 int main(void) { char b[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F',}; int c[64],d,i=0,base; long n; printf("enter a number : "); scanf("%ld",&n); printf("enter new base : "); scanf("%d",&base); do{ c[i]=____; i++; n= n╱base; } while (n!=0 ); printf("transmite new base: "); for (--i;i>=0;--i){ d=c[i]; printf("%c",____);} return 0;}"

以下程序调试结果为：private class Base{ ....out.println(i); }}

下面程序是将十进制数转换成不超过十六进制的n进制。请分析程序填空。 #include main() { int i=0,base,n,j,num[20]; printf("Enter data that will be converted:\n"); scanf("%d",&n); printf("Enter base:\n"); scanf("%d",&base); do { i++; num[i]=n【1】base; n=n【2】base; } while(n); printf("The data %d has been converted into the %d base data:\n",n,base); for(【3】) if(num[j]>9) putchar(num[j]+'A'-10); else putchar(num[j]+'0'); }

When you finish your resume, read it over, and ask yourself, "(Base) _____ on this resume, would I hire this applicant?"