用2片容量为8K×8的RAM构成容量为16K×8的RAM是位扩展。( )
用2片容量为8K×8的RAM构成容量为16K×8的RAM是位扩展。( )
把 \(1kg\),\(20^\circ C\) 的水放到温度恒为 \(500^\circ C\) 的炉子上加热,最后水温达到 \(100^\circ C\)。在这个过程中,水和炉子的熵变分别为 [已知水的比热为\(4.18 \times 10^3 J/(kg \cdot {^\circ C)}\)] A: \(1.01 \times 10^3 J/K\),\(–0.43 \times 10^3 J/K\)。 B: \(1.01 \times 10^3 J/K\),\(–0.90 \times 10^3 J/K\)。 C: \(0.90 \times 10^3 J/K\),\(–0.43 \times 10^3 J/K\)。 D: \(0.90 \times 10^3 J/K\),\(–0.90 \times 10^3 J/K\)。
把 \(1kg\),\(20^\circ C\) 的水放到温度恒为 \(500^\circ C\) 的炉子上加热,最后水温达到 \(100^\circ C\)。在这个过程中,水和炉子的熵变分别为 [已知水的比热为\(4.18 \times 10^3 J/(kg \cdot {^\circ C)}\)] A: \(1.01 \times 10^3 J/K\),\(–0.43 \times 10^3 J/K\)。 B: \(1.01 \times 10^3 J/K\),\(–0.90 \times 10^3 J/K\)。 C: \(0.90 \times 10^3 J/K\),\(–0.43 \times 10^3 J/K\)。 D: \(0.90 \times 10^3 J/K\),\(–0.90 \times 10^3 J/K\)。
2164A芯片是一个( )的芯片。 A: 64K×1b B: 8K×8b C: 8K×1b D: 2K×8b
2164A芯片是一个( )的芯片。 A: 64K×1b B: 8K×8b C: 8K×1b D: 2K×8b
6116芯片是一个( )的芯片。 A: 8K×1b B: 64K×1b C: 8K×8b D: 2K×8b
6116芯片是一个( )的芯片。 A: 8K×1b B: 64K×1b C: 8K×8b D: 2K×8b
In Life and Times of Michael K, K’s birth defect is related to one of the themes of the novel.
In Life and Times of Michael K, K’s birth defect is related to one of the themes of the novel.
How many times will the loop body be executed? int k=0; while(k=1)k++;
How many times will the loop body be executed? int k=0; while(k=1)k++;
Normally a person urinates A: 8 eight times per day B: 3~5 times per day C: 5~7 times per day D: 2~3 times per day
Normally a person urinates A: 8 eight times per day B: 3~5 times per day C: 5~7 times per day D: 2~3 times per day
In Life and Times of Michael K, pumpkin seeds represent hope and life.
In Life and Times of Michael K, pumpkin seeds represent hope and life.
At the beginning of Life and Times of Michael K,,K is still hopeful of his life and realizing his mother’s dream.
At the beginning of Life and Times of Michael K,,K is still hopeful of his life and realizing his mother’s dream.
以下程序的输出结果是______。 #define TIMES(X) X*X main() int a=16,k=2,m=1; a/=TIMES (k+m)/TIMES(k+m); printf("d\n", A: ; B: &n
以下程序的输出结果是______。 #define TIMES(X) X*X main() int a=16,k=2,m=1; a/=TIMES (k+m)/TIMES(k+m); printf("d\n", A: ; B: &n